Answer:
V₂=4.57 x 10³ L
Explanation:
Given that
V₁= 2.88 x 10³ L
P₁=722 mm Hg
T₁ = 19°C
T₁ =292 K
P₂=339 mm Hg
T₂= - 55°C
T₂=218 K
Lets take final volume = V₂
We know that ideal gas equation
PV = m R T
By applying mass conservation


V₂=4.57 x 10³ L
Therefore volume will be 4.57 x 10³ L
Answer:
Explanation:
Let equal mass of Ne and Kr be m gm
no of moles of Ne and Kr will be m / 20 and m / 84 ( atomic weight of Ne and Kr is 20 and 84 )
Let the pressure and volume of both the gases be P and V respectively .
The temperature of Ne be T₁ and temperature of Kr be T₂.
For Ne
PV = (m / 20) x R T₁
For Kr
PV = (m / 84) x R T₂
T₁ / T₂ = 84 / 20
We know that
average KE of an atom of mono atomic gas = 3 / 2 x k T
k is boltzmann constant and T is temperature .
KEKr/KENe = T₂ / T₁
= 20 / 84
Answer:
B.The linear velocity of the gears is the same. The linear velocity is 432π centimeters per minute.
Explanation:
As we know that the small gear completes 24 revolutions in 20 seconds
so the angular speed of the smaller gear is given as


Now we know that the tangential speed of the chain is given as

so we have



Since both gears are connected by same chain so both have same linear speed and hence correct answer will be
B.The linear velocity of the gears is the same. The linear velocity is 432π centimeters per minute.
For a concave mirror, the radius of curvature is twice the focal length of the mirror:

where f, for a concave mirror, is taken to be positive.
Re-arranging the formula we get:

and since the radius of curvature of the mirror in the problem is 24 cm, the focal length is