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Answer 1

$\sf \huge \purple{ Question : - }$

Initial velocity of a car is 36 km/h . Find the distance after min, if it goes with acceleration 2 m/s².

$\sf \huge \color {gold}{ AnSwer :- }$

Initial velocity, u = 36 km/h

$\sf u = 36 \times \dfrac{5}{18} {ms}^{ - 1} = 10 {ms}^{ - 1}$

Time, t = 1min

• t = 60s

Acceleration, a = 2m/s²

Apply 2nd equation of motion

$\longrightarrow \sf s = ut + \dfrac{1}{2} at ^{2} \\ \\ \longrightarrow \sf s =(10)(60) + \frac{1}{2} (2)(60) {}^{2} \\ \\ \longrightarrow \sf s =600 + 3600 \\ \\ \longrightarrow \sf \blue{ s =4200m} \: \: \large \blue \star$