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garik1379 [7]
3 years ago
5

To solve 9x^2-12x+4=49 by using the Square Root Property, you would first rewrite the equation was as

Mathematics
1 answer:
uranmaximum [27]3 years ago
8 0

Given:

The equation is

9x^2-12x+4=49

To find:

The equation after first step to solve the given equation by using square root property.

Solution:

We have,

9x^2-12x+4=49

It can be written as

(3x)^2-2(3x)(2)+(2)^2=49

(3x-2)^2=49            [\because (a-b)^2=a^2-2ab+b^2]

Therefore, the equation can be rewritten in first step as (3x-2)^2=49.

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decimal=0.625

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Step-by-step explanation:

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4 years ago
Given f(x), find g(x) and h(x) such that f(x)=g(h(x)) and neither g(x) nor h(x) is solely x. f(x)=−3x+4⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯√3+5
iVinArrow [24]

Answer:

h(x)=-2x+4

g(x)=\sqrt[3]{x}-5

Step-by-step explanation:

Consider the given function is

f(x)=\sqrt[3]{-2x+4}-5

It is given that f(x)=g(h(x)) and neither g(x) nor h(x) is solely x.

f(x)=\sqrt[3]{(-2x+4)}-5

Let h(x)=-2x+4, then we get

f(x)=g(h(x))=\sqrt[3]{h(x)}-5

Substitute h(x)=x in the above function.

g(x)=\sqrt[3]{x}-5

Therefore, the required functions are h(x)=-2x+4 and g(x)=\sqrt[3]{x}-5.

Check the solutions.

g(h(x))=g(-2x+4)             [\because h(x)=-2x+4]

g(h(x))=\sqrt[3]{-2x+4}-5            [\because g(x)=\sqrt[3]{x}-5]

g(h(x))=f(x)

Therefore, our solution is correct.

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4 years ago
I need help with both please no links!
nlexa [21]

Answer:

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Step-by-step explanation:

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3 years ago
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Tomtit [17]
Yeah I think it’s 12 hope that helped...
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3 years ago
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