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katovenus [111]
3 years ago
9

For the reaction, calculate how many grams of the product form when 23.4 g of ca completely reacts. assume that there is more th

an enough of the other reactant.
Chemistry
1 answer:
Bond [772]3 years ago
3 0
Answer is: mass of product is 649.35 g.
Balanced chemical reaction: Ca(s)+Cl₂<span>(g) → CaCl</span>₂<span>(s).
m(Ca) = 23.4 g.
n</span>(Ca) = m(Ca) ÷ M(Ca).
n(Ca) = 23.4 g ÷ 40 g/mol.
n(Ca) = 0.585 mol.
From chemical reaction: n(Ca) : n(CaCl₂) = 1 : 1.
n(CaCl₂) = 0.585 mol.
m(CaCl₂) = 0.585 mol · 111 g/mol.
m(CaCl₂) = 649.35 g.
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