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Elis [28]
3 years ago
7

Using the formula C = 2πr, find the circumference of a circle with diameter of 28 inches. Round your answer to the nearest inch.

Mathematics
2 answers:
Whitepunk [10]3 years ago
7 0
The equation asks for radius, therefore, take half of 28 (diameter), which is 14.

Substitute 14 into the equation.

C =2(pi)(14)
C = 87.96

Your answer is C!
lesya [120]3 years ago
5 0
The answer my friend is b
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Sophie [7]

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Problem 4:
Kipish [7]

Answer:

12cm and 16cm

Step-by-step explanation:

The hypotenuse of the right angle triangle  = 20cm

 let the other two sides be x and y;

 The difference;

                x  = y - 4

Problem:

Find x and y;

Solution:

According to the pythagoras theorem;

    x² + y² = 20²  ------ i

       x² + y² = 400 ----- i

and  x - y = 4 ---- ii

So;   x = 4 + y

Now input the value into equation (i);

  (y + 4)² + y² = 400

   (y+4)(y+4) + y² = 400

    y² + y² + 4y + 4y + 16 = 400

    2y² + 8y + 16 = 400

    2y² + 8y + 16 -400 = 0

   2y² + 8y - 384 = 0;

      y² + 4y - 192 = 0

Factorize the equation;

  y² + 16y - 12y - 192 = 0

  y(y + 16) - 12(y + 16) = 0

  (y-12)(y + 16) = 0

     y -12 = 0 or y+ 16 = 0

     y = 12 or -16

It is not realistic for the length of a body to be a negative value, so y= 12;

   since;

    x - y = 4,

    x = 4 + 12

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5 0
4 years ago
The star shape is made from a regular hexagon and six congruent equilateral triangles The area of the star shape is 96cm squared
svlad2 [7]

Answer:

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The area of one red equilateral triangle is some area A.

There are 6 of these red triangles, so the red exterior triangular parts combine to a total area of 6*A.

The hexagon is composed of equilateral triangles as well.

Each of these blue equilateral triangles is congruent to any outer red triangle because the side length is the same.

Therefore, the 6 blue equilateral triangles composing this hexagon combine to get a total area of 6*A

The area of the star overall is 12*A because we have 6 blue triangles combining with the 6 red triangles.

There is a total of 12 triangles.

7 0
2 years ago
Where is the transverse axis of the hyperbola x^2-4y^2=16
Anton [14]
 <span> <span>x^2-4y^2=16</span></span>

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