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Effectus [21]
3 years ago
8

A quality control officer is randomly checking the weights of sugar bags being filled by an automatic filling machine. Each bag

is advertised as weighing 1000 grams. A bag must weigh within 2.3 grams in order to be accepted. What is the range of rejected bags, x, for the bags of sugar?
Mathematics
2 answers:
Misha Larkins [42]3 years ago
5 0

Answer:

997.7>x>1002.3

Step-by-step explanation:

Given : Each bag is advertised as weighing 1000 grams.

            A bag must weigh within 2.3 grams in order to be accepted.

To Find : What is the range of rejected bags, x, for the bags of sugar?

Solution:

Each bag is advertised as weighing 1000 grams.

A bag must weigh within 2.3 grams in order to be accepted.

So, The acceptance range for x bags : 1000-2.3

                                               997.7

So, The bag must weighs more than 997.7 grams and should be less than 1002.3 grams

So, The range of rejected bags, x, for the bags of sugar is when  The bag must weight less than 997.7 grams and more than 1002.3 grams

So, The range of rejected bags, x, for the bags of sugar:997.7>x>1002.3

lisov135 [29]3 years ago
4 0
The answer is x=0.065217391 kilograms
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Please answer this quickly !
nika2105 [10]

Answer:

The first option.

Because we're solving for the price of each gallon, x will represent the cost of each gallon. Since 8.4 is the total amount of gallons, multiply 8.4 and x to get $23.94. Solve for x by dividing 23.94 to get $2.85 per gallon. To check this, substitute 2.85 for x into the equation: 8.4 (2.85) = 23.94

4 0
3 years ago
Transform the equation to isolate x: ax = bx + 1. How is the value of x related to the difference of a and b? The equation ax =
butalik [34]

Answer:Transform the equation to isolate x: ax = bx + 1. How is the value of x related to the difference of a and b

Step-by-step explanation:

4 0
3 years ago
Point R is on line segment QS. Given QS= 5x-2, QR= 3x-6, and RS=4x-2, determine the numerical length of RS.
pashok25 [27]

Answer:

The numerical length of RS is 10 units

Step-by-step explanation:

* <em>Lets explain How to solve the problem</em>

- Point R is on line segment QS

- The length of QS is (5x - 2)

- The length of QR is (3x - 6)

- The length of RS is (4x - 2)

- <em>The length of QS is the sum of the lengths of QR and RS</em>

∵ QS = QR + RS

∴ (5x - 2) = (3x - 6) + (4x - 2)

- Simplify the right hand side by adding like terms

∴ 5x - 2 = (3x + 4x) + (-6 + -2)

∴ 5x - 2 = 7x + -8 ⇒ (+)(-) = (-)

∴ 5x - 2 = 7x - 8

- Add 8 for both sides

∴ 5x + 6 = 7x

- Subtract 5x from both sides

∴ 6 = 2x

- Divide both sides by 2

∴ x = 3

- <em>To find the length of RS substitute the value of x in its expression</em>

∵ RS = 4x - 2

∵ x = 3

∴ RS = 4(3) - 2 = 12 - 2 = 10

∴ The numerical length of RS is 10 units

8 0
4 years ago
Fernell and Dabney shared the driving
Agata [3.3K]

Answer:

15 hours

Step-by-step explanation:

Given:

Fernell's speed v_F= 50 mph

Dabney's speed v_D= 64 mph

Denote:

D_F - distance covered by Fernell

D_D - distance covered by Dabney

t_F - Fernell's time

t_D - Dabney's time

1. If Fernell drove for 3 hours longer than Dabney, then his time is 3 hours more than Dabney's time and

t_F=t_D+3

2. If Fernell covered 18 miles less than Dabney, then

D_D-D_F=18

Use formula D=t\cdot v

D_D=v_D\cdot t_D\Rightarrow D_D=64\cdot t_D\\ \\D_F=v_F\cdot t_F\Rightarrow D_F=50\cdot (t_D+3)

Subtract from the first equation the second equation and equate it to 18:

64t_D-50(t_D+3)=18\\ \\64t_D-50t_D-150=18\\ \\14t_D=168\\ \\t_D=12\ \text{hours}

t_F=t_D+3=12+3=15\ \text{hours}

5 0
3 years ago
Which expression is equivalent to 250 + 150 ?
salantis [7]

Answer:

if 25c + 15d = 0, then d = -25/15c

Step-by-step explan

just yes, that

3 0
3 years ago
Read 2 more answers
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