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3 years ago

#3 a and b both help answer

Mathematics

1 answer:

quester [9]3 years ago

5 0

Answer:

$9.96, 125

Step-by-step explanation:

2.99x4= 11.96-2.00=9.96

15x3=45+20x4= 125

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Find the Value of x from the following :

Sonja [21]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

<h3>Question 1 ~</h3>

$log_{x}(64) = 2$

${x}^{2} = 64$

$x = \sqrt{64}$

$x = \sqrt{8 \times 8}$

$x = 8$

<h3>Question 2 ~</h3>

$log_{2}(x) = 5$

$x = 2 {}^{5}$

$x = 32$

I hope it helped ~

7 0

3 years ago

I need 2 and 4! So please help me thx :)

katen-ka-za [31]

2. final answer 3/4

Multiplying a positive and a negative equals a negative

3 x -1/4

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-3/4 < — final answer

8 0

3 years ago

ܝܐ55.XVZܢ<br> ܟܝܐ-)X<br> (<br> 65<br> )<br> ,<br> y<br> (<br> 6<br> ,<br> -352Z<br> ܂'S-

Elina [12.6K]

Answer:

Step-by-step explanation:

4 0

3 years ago

The mean salary of actuaries is LaTeX: \mu=\$100,000????=$100,000 and the standard deviation is LaTeX: \sigma=\$36,730????=$36,7

krek1111 [17]

Answer:

The lower limit of 95% confidence interval is 99002.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = $100,000

Sample mean, $\bar{x}$ = $111,000

Sample size, n = 36

Alpha, α = 0.05

Population standard deviation, σ = $36,730

First, we design the null and the alternate hypothesis

$H_{0}: \mu = \$100,000\\H_A: \mu \neq \$100,000$

We have to find the lower limit of the 95% confidence interval.

95% Confidence interval:

$\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}$

Putting the values, we get,

$z_{critical}\text{ at}~\alpha_{0.05} = 1.96$

$111000 \pm 1.96(\dfrac{36730}{\sqrt{36}} )\\\\ = 111000 \pm 11998.4667 \\= (99001.5333,122998.4667)\\ \approx (99002,122999)$

The lower limit of 95% confidence interval is 99002.

6 0

4 years ago

2x⁴-6x²+3 divided by 2x-6

kow [346]

Step-by-step explanation:

answer is 552€₹%+×::!^*I HOPE ITS CORRESCT

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3 years ago