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shutvik [7]
3 years ago
15

#3 a and b both help answer

Mathematics
1 answer:
quester [9]3 years ago
5 0

Answer:

$9.96, 125

Step-by-step explanation:

2.99x4= 11.96-2.00=9.96

15x3=45+20x4= 125

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Sonja [21]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

<h3>Question 1 ~</h3>

  • log_{x}(64)  = 2

  • {x}^{2}  = 64

  • x =  \sqrt{64}

  • x =  \sqrt{8 \times 8}

  • x = 8
<h3>Question 2 ~</h3>

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I hope it helped ~

7 0
3 years ago
I need 2 and 4! So please help me thx :)
katen-ka-za [31]
2. final answer 3/4


Multiplying a positive and a negative equals a negative

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3 years ago
ܝܐ55.XVZܢ<br> ܟܝܐ-)X<br> (<br> 65<br> )<br> ,<br> y<br> (<br> 6<br> ,<br> -352Z<br> ܂'S-
Elina [12.6K]

Answer:

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Step-by-step explanation:

4 0
3 years ago
The mean salary of actuaries is LaTeX: \mu=\$100,000????=$100,000 and the standard deviation is LaTeX: \sigma=\$36,730????=$36,7
krek1111 [17]

Answer:

The lower limit of 95% confidence interval is 99002.

Step-by-step explanation:

We are given the following in the question:

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Sample mean, \bar{x} = $111,000

Sample size, n = 36

Alpha, α = 0.05

Population standard deviation, σ = $36,730

First, we design the null and the alternate hypothesis

H_{0}: \mu = \$100,000\\H_A: \mu \neq \$100,000

We have to find the lower limit of the 95% confidence interval.

95% Confidence interval:

\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}

Putting the values, we get,

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

111000 \pm 1.96(\dfrac{36730}{\sqrt{36}} )\\\\ = 111000 \pm 11998.4667 \\= (99001.5333,122998.4667)\\ \approx (99002,122999)

The lower limit of 95% confidence interval is 99002.

6 0
4 years ago
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kow [346]

Step-by-step explanation:

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