Answer:
the woman has to live 1 mile from work to minimize the expenses
Step-by-step explanation:
Given the data in the question;
the distance within 9 miles ⇒ 0 < x > 9
Total costs Q = cx + 4c/( x + 1)
costs should be minimum ⇒ dQ/dx = 0
⇒ d/dx [ cx + 4c/( x + 1) ] = 0
⇒ ( x + 1)² = 4
take square root of both side
√[ ( x + 1)² ] = √4
x + 1 = 2
x = 2 - 1
x = 1
Therefore, the woman has to live 1 mile from work to minimize the expenses
Answer:
welll the answer is 32.5 as used in the expression
Step-by-step explanation:
-2.5 plot it on a line graph then cooridinate the x and y axis to 35 and add the summ up to get 32.5
Good evening ,
______
Answer:
1) (f+g)(1) = e
2) (fg)(1) = 0
3) (3f)(1) = 3e
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Step-by-step explanation:
1) (f+g)(1) = f(1) + g(1) = e¹ + log1 = e + 0 = e.
2) (fg)(1) = f(1) × g(1) = e¹ × log(1) = e¹ × 0 = e × 0 = 0.
3) (3f)(1) = 3×f(1) = 3×e¹ = 3e.
:)
To add fractions they're suppose to have the same base or denominator then u add the top
To subtract it's the same but u subtract the top
So the perimeter(P) of a rectangle would be:
P= 2L+2W
L being the length and W being the width.
The problem says the length is 4cm more than the width, so L= 4+W.
So if we substitute L with 4+W, we get:
P= 2(4+W) + 2W
Use the Distributive Property
P= 8+2W+2W
Combine like terms
P=8+4W
Since we're given the perimeter, we could replace P with 52. So:
52=8+4W
Subtract 8 to both sides
44=4W
Divide 4 to both sides
11=W
Therefore, the width is 11cm
And since the length is 4cm more than the width, we could add 4cm to 11cm to find that the length is 15cm
Thus, the dimensions of the rectangle are 15cm by 11cm
