Question

Find the exact value of sin(θ) for an angle θ with sec(θ) = 5/2 and with its terminal side in Quadrant IV.

Answer 1

Answer:

Option B

Explanation:

Please see attached picture for full solution.

Y has to be negative since it lies below the x axis.

In 4th quadrant, only the cosine of an angle is positive.

Answer 2

Answer:

B

Step-by-step explanation:

(Sorry about the crude drawing)

The drawing shows what the triangle with a terminal side in Quadrant IV looks like.

Secant is the ratio of the hypotenuse to the adjacent side of the angle. In the given ratio, we can set 5 as the hypotenuse and 2 as the adjacent side (you can see them labeled in the picture).

Now, we want to find sin, which is (opposite)/(hypotenuse). However, we don't know the opposite. We can find it by using the Pythagorean Theorem:

$\sqrt{5^2-2^2} =\sqrt{25-4} =\sqrt{21}$

So, the opposite side is $\sqrt{21}$. But, we see that since it's in the fourth quadrant, it must be negative, so we have opposite = $-\sqrt{21}$. Now, we can find the ratio because hypotenuse = 5:

sin(θ) = $-\sqrt{21} /5$.

Thus, the answer is B.

Hope this helps!