<h3>
Answer: Choice A</h3>
- Domain: x > 4
- Range: y > 0
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Explanation:
We want to avoid having a negative number under the square root. Solving
leads to 
So it appears the domain could involve x = 4 itself; however, if we tried that x value, then we'd get a division by zero error.
So in reality, the domain is x > 4.
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The range of y = sqrt(x) is the set of positive real numbers. So y > 0 is the range for this equation. Shifting left and right does not affect the range, so the range of y = sqrt(x-4) is also y > 0.
We are dividing a positive number (3) over some positive number in the denominator. Overall, the expression
is positive because positive/positive = positive.
Therefore, the range of the given equation is y > 0
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The graph is shown below. We have a vertical asymptote at x = 4 and a horizontal asymptote at y = 0. The green curve is fenced in the upper right corner (northeast corner).
Answer:
Step-by-step explanation:
No. Each side must be less than the sum of the remaining two sides.
10 ≮ 5+1
Answer:
532m squared is the answer
Step-by-step explanation:
Split the shape into two shapes
one will be a square and the other one a triangle
1) since the length and the width of the square is 18m just Multiply
18x18=324m squared
2) look carefully the width of the square you split is equal to the base of the triangle, so you connect the 18 and the 8 together.
18+8=26m squared
3) Now solve the triangle since you know the height which is 16m squared.
A=lw/2
26x16=416
416 divided by 2 is 208
4) finally just Add
208+324=532m squared
Hopes this helps!
I wanna say 10 or ether -10 since if it was subtracted from 2 then it would equal -8