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Harrizon [31]
3 years ago
14

the length of a rectangle is 5 minutes longer than its with if the perimeter of the rectangle must be at least 34 units what are

the possible lamps of the rectangle right in any quality to represent the problem then solve the inequality​
Mathematics
1 answer:
stealth61 [152]3 years ago
7 0

Answer:

w ≥ 6

l ≥ 11

Step-by-step explanation:

The perimeter of a rectangle is equal to P = 2l+2w where l=length and w=width. Here the length is 5 feet longer than the width or 5+w. This means the width is w. Substitute P = 34, l=5+w and w into the perimeter equation. Then solve for w.

34 ≤ 2*(5+w) + 2w

34 ≤ 10+2w+2w

34 ≤ 10+4w

24 ≤ 4w

6 ≤ w

This means the width must be at least 6 so the solution is w ≥ 6.

To find the length substitute 6 into l ≤ 5+w.

l ≤ 5 + 6

l ≤ 11

The length is l ≥ 11.

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GrogVix [38]

Answer:

first one: <u>3</u>

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Step-by-step explanation:

first one:

21 x ________ ÷ 3 = 21

rewrite equation:

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3 years ago
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8 0
2 years ago
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Find the value.<br> 9x+6 when x=-2/3
OLEGan [10]

Answer:

<h2>0</h2>

Step-by-step explanation:

Given,

-  \frac{2}{3}

Now, let's find the value of 9x + 6

9x + 6

plug the value of X

= 9 \times  (-  \frac{2}{3} ) + 6

Multiplying a positive and negative equals a negative

( + ) \times ( - ) = ( - )

=  - 9 \times  \frac{2}{3}  + 6

Reduce the number with Greatest Common Factor 3

=  - 3 \times 2 + 6

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=  - 6 + 6

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Hope this helps..

best regards!!

7 0
3 years ago
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DochEvi [55]
Integers I believe :) hope this helps
5 0
2 years ago
The figure shows the dimensions of a wall having a door and window of a room. Write an algebraic expression for the area of the
qwelly [4]

Answer:

Area of the wall to be painted = (11x² + 12x) square units

Step-by-step explanation:

The figure that should be attached to this question is missing. The figure was obtained and is attached to this solution provided.

From the image attached, it is given that the dimension of the rectangular wall to be painted is (4x+3) by (4x), the dimensions of the window is (2x) by (x) and the dimensions of the door is (x) by (3x).

Since, the window space and the door space cannot be painted along with the wall, the Area of the rectangular wall that will be painted will be given by the expression

(Total Area of the rectangular wall) - [(Area of window space) + (Area of door space)]

Area of a rectangular figure = Length × Breadth

Total area of rectangular wall = (4x+3) × 4x = (16x² + 12x) square units

Area of window space = (2x) × (x) = (2x²) square units

Area of door space = (x) × (3x) = (3x²) square units

Area of the wall to be painted = (16x² + 12x) - (2x² + 3x²)

= 16x² + 12x - 5x²

= (11x² + 12x) square units

Hope this Helps!!!

6 0
3 years ago
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