Given that the terminal side of an <θ intersects the unit circle at the point
![P(\frac{5}{6},\frac{-\sqrt[]{11}}{6})](https://tex.z-dn.net/?f=P%28%5Cfrac%7B5%7D%7B6%7D%2C%5Cfrac%7B-%5Csqrt%5B%5D%7B11%7D%7D%7B6%7D%29)
From the given point P:
![\begin{gathered} x=\frac{5}{6} \\ y=\frac{-\sqrt[]{11}}{6} \\ \text{ s}ince,\text{ x is positive and y is negative, the angle lies in the 4th quadrant} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x%3D%5Cfrac%7B5%7D%7B6%7D%20%5C%5C%20y%3D%5Cfrac%7B-%5Csqrt%5B%5D%7B11%7D%7D%7B6%7D%20%5C%5C%20%5Ctext%7B%20s%7Dince%2C%5Ctext%7B%20x%20is%20positive%20and%20y%20is%20negative%2C%20the%20angle%20lies%20in%20the%204th%20quadrant%7D%20%5Cend%7Bgathered%7D)
<span>Jim's rate = x tiles/hr
Pete's rate = (x+25) tiles/hr
Number of tiles Jim lays = 12x
Number of tiles Pete lays = 10(x+25)
Since both lay same number of tiles
B. 12x = 10(x+25) </span>
For the number 3.48 we have:
We multiply and divide the number by 100:
![3.48 * (\frac{100}{100}) =\frac{348}{100}](https://tex.z-dn.net/?f=%203.48%20%2A%20%28%5Cfrac%7B100%7D%7B100%7D%29%20%3D%5Cfrac%7B348%7D%7B100%7D%20%20%20%20)
We simplify the fraction obtained.
![\frac{348}{100} =\frac{87}{25}](https://tex.z-dn.net/?f=%20%5Cfrac%7B348%7D%7B100%7D%20%3D%5Cfrac%7B87%7D%7B25%7D%20%20%20)
Answer:
3.48 repeating as a fraction is:
![3.48 = \frac{87}{25}](https://tex.z-dn.net/?f=%203.48%20%3D%20%5Cfrac%7B87%7D%7B25%7D%20%20)
For the number 1.07 we have:
We multiply and divide the number by 100:
![1.07 * (\frac{100}{100}) =\frac{107}{100}](https://tex.z-dn.net/?f=%201.07%20%2A%20%28%5Cfrac%7B100%7D%7B100%7D%29%20%3D%5Cfrac%7B107%7D%7B100%7D%20%20%20)
The fraction obtained can not be simplified because we do not have multiples of the numerator and denominator equal.
Answer:
1.07 repeating as a fraction is:
![1.07 = \frac{107}{100}](https://tex.z-dn.net/?f=%201.07%20%3D%20%5Cfrac%7B107%7D%7B100%7D%20)
Answer:
50% probably
Step-by-step explanation:
well how many options are there
think 1/? ? being how many options there are and 1 being the 1 option to pick aquarium