gradient is 2
Step-by-step explanation:
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Answer:
Let P be the external point. O be the origin. join O and P get OP and nearest point on the circle from P be A.
Let Q be the point onthe circle in which, tangent make 90° with radius at Q.
PQ = 8 and OQ = 6
we get a right angled triangle PQO right angled at Q.
so, OP^2 = OQ^2 + PQ^2= 8^2 + 6^2 = 64 + 36 =1==
therefore OP =10cm
we need nearest point from P, which is PA
PA = OP - OA= 10 -6=4cm
-3•-4=12, and -3+-4=-7.
this will turn into
(x-3)(x-4)
set them up to equal zero
x-3=0, x-4=0
solve
x=3, x=4
(a)
