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laiz [17]
3 years ago
8

nert xenon actually forms many compounds, especially with highly electronegative fluorine. The ΔH o f values for xenon difluorid

e, tetrafluoride, and hexafluoride are −105, −284, and −402 kJ/mol, respectively. Find the average bond energy of the XebondF bonds in each fluoride.
Physics
1 answer:
loris [4]3 years ago
3 0

Answer:

For Xenon fluoride, the average bond energy is 132kj/mol

For tetraflouride,the average bond energy is 150.5kj/mol.

For hexaflouride, the average bond energy is 146.5 kj/mol

Explanation:

For xenon fluoride

105/2 = 52.5

For F-F

159/2 = 79.5

Average bond energy of Xe-F = 79.5 + 52.5 = 132kj/mole

For tetraflouride

284/4 = 71

For F-F

159/2 = 79.5

Average bond energy = 79.5 + 71 = 150.5kj/mol

For hexaflouride

402/6 = 67

F-F = 159/2 = 79.5

Average bond energy = 67 + 79.5 = 146.5kj/ mol

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2 years ago
A space walking astronaut has become detached from her spaceship.shes floating in space while holding a wrench she is thinking a
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Answer:

Newton's third law of motion states that for every action, there is equal and opposite reaction.

While space walking, when the astronaut gets detached from the space ship, she floats in space holding a wrench. In order to get back to the spaceship, she should throw the wrench in the opposite direction of the spaceship. This action would  cause a reaction on her own body and she would be pushed away from the wrench and towards the spaceship. Thus, she can return back to the spaceship in this way.

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3 years ago
Assume that you have two objects, one with a mass of 6 kg and the other with a mass of 17 kg, each with a charge of −0.027 c and
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3 years ago
The maximum stress in a section of a circular tube subject to a torque is τmax = 27 MPa . If the inner diameter is Di = 3.75 cm
DIA [1.3K]

Answer:

T_{max} = 4.735\,kN\cdot m

Explanation:

The shear stress due to torque can be calculed by using the following model:

\tau_{max} = \frac{T_{max}\cdot r_{ext}}{J_{tube}}

The maximum torque on the section is:

T_{max} = \frac{\tau_{max}\cdot J_{tube}}{r_{ext}}

The Torsion Constant for the circular tube is:

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J_{tube} = 4.560\times 10^{-6}\,m^{4}

Now, the require output is computed:

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T_{max} = 4.735\,kN\cdot m

7 0
3 years ago
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A deer walks 17.0 m south and then 12.0 m north. Find both the magnitude of its displacement and the distance traveled.
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Answer:

Explanation:

Displacement involves direction and distance.  In this case, the deer has walked a distance of 17 + 12 = 29m but because of the South-then-North direction, the net displacement is only 17-12 = 5m.

So the answer is A)   5.0 m, 29.0 m

7 0
3 years ago
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