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MAXImum [283]
3 years ago
12

What changes when unbalanced forces are appiled to a moving bike along the direction it is moving

Physics
1 answer:
Inga [223]3 years ago
5 0

Answer:

D. Velocity

Explanation:

It is velocity because inertia doesn't have any movement, friction is the resistance that one surface or object encounters when moving over to another, and mass is a large body of matter with no definite shape.Velocity means the speed of something given direction which explains the question

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How does the "lollipop moment", exemplify for us the opportunity we all have to exercise leadership on a normal everyday basis?
Mrrafil [7]

Answer:

WHat do you mean by that

Explanation:

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8 0
3 years ago
What is the all time speed record for completing the iditarod?.
shtirl [24]
<h3>Question:</h3>

•What is the all time speed record for completing the iditarod?

Answer:

•In 2016, Dallas broke his own record, finishing in 8 days, 11 hours, 20 minutes and 16 seconds. In 2017, Mitch Seavey broke all previous records by finishing in 8 days, 3 hours, 40 minutes and 13 seconds, which currently stands as the fastest winning time for the Iditarod.

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3 0
2 years ago
On what criteria is the Fujita scale for Tornadoes based?
svp [43]
B. Tornado destruction
It is based on the amount of damage
7 0
3 years ago
What is the average speed of a car that moves 570 m in 24 s
Sladkaya [172]
The formula for speed is:
Speed = Distance/Time
We can plug in the given values into the above equation:
Speed = 570m÷24s
Speed = 23.75, which rounds to 24m/s as a whole number. Therefore, the answer is b.
7 0
3 years ago
The magnitude J(r) of the current density in a certain cylindrical wire is given as a function of radial distance from the cente
Gennadij [26K]

Answer:

18.1 × 10⁻⁶ A = 18.1 μA

Explanation:

The current I in the wire is I = ∫∫J(r)rdrdθ

Since J(r) = Br, in the cylindrical wire. With width of 10.0 μm, dr = 10.0 μm. r = 1.20 mm. We have a differential current dI. We integrate first by integrating dθ from θ = 0 to θ = 2π.

So, dI = J(r)rdrdθ

dI/dr = ∫J(r)rdθ = ∫Br²dθ = Br²∫dθ = 2πBr²

Now I = (dI/dr)dr at r = 1.20 mm = 1.20 × 10⁻³ m and dr = 10.0 μm = 0.010 mm = 0.010 × 10⁻³ m

I = (2πBr²)dr = 2π × 2.00 × 10⁵ A/m³ × (1.20 × 10⁻³ m)² × 0.010 × 10⁻³ m  =  0.181 × 10⁻⁴ A = 18.1 × 10⁻⁶ A = 18.1 μA

3 0
3 years ago
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