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OleMash [197]
3 years ago
10

1.) What is the equation for Average Speed?

Physics
2 answers:
Sphinxa [80]3 years ago
7 0
Speed = distance times time
jok3333 [9.3K]3 years ago
4 0

Answer:

Speed = Distance / Time

Explanation:

here you go :)

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American eels (Anguilla rostrata) are freshwater fish with long, slender bodies that we can treat as a uniform cylinder 1.0 m lo
madam [21]

Answer:

option D

Explanation:

given,

uniform length of cylinder = 1 m

diameter of the cylinder = 10 cm = 0.1 m

Eels have been recorded to spin = 14 rev/s

camera records at = 120 frames per second

time = \dfrac{1}{120}\ s/frame

angle at which eel rotate = ?

ω = 14 rev/s

ω = 14 x 2 π rad/s

ω = 28 π rad/s

angle at which eel rotate

 θ = ω t

θ = 28\pi\times \dfrac{1}{120}

θ = 0.733 rad

θ =0.733 \times \dfrac{180^0}{2\pi}

θ =42^0

Hence, the correct answer is option D

4 0
3 years ago
An atom of 6/2 He decays by beta decay. What atom is left after decay
olya-2409 [2.1K]

Answer:

6/3 LI

Explanation:

7 0
3 years ago
A force of 5.0 N acts on a 15 kg body initially at rest. Compute the work done by the force in (a) the first, (b) the second, an
Leokris [45]

Answer:

(a) 0.833 j

(b) 2.497 j

(c)  4.1625 j

(d) 4.995 watt      

Explanation:

We have given force F = 5 N

Mass of the body m = 15 kg

So acceleration a=\frac{F}{m}=\frac{5}{15}=0.333m/sec^2

As the body starts from rest so initial velocity u = 0 m/sec

(a) From second equation of motion s=ut+\frac{1}{2}at^2

For t = 1 sec

s=0\times 1+\frac{1}{2}\times 0.333\times 1^2=0.1666m

We know that work done W =force × distance = 5×0.1666 =0.833 j

(b) For t = 2 sec

s=0\times 2+\frac{1}{2}\times 0.333\times 2^2=0.666m

We know that work done W =force × distance = 5×0.666 =3.33 j

So work done in second second = 3.33-0.833 = 2.497 j

(c) For t = 3 sec

s=0\times 3+\frac{1}{2}\times 0.333\times 3^2=1.4985m

We know that work done W =force × distance = 5×1.4985 =7.4925 j

So work done in third second = 7.4925 - 2.497 -0.833 = 4.1625 j

(d) Velocity at the end of third second v = u+at

So v = 0+0.333×3 = 0.999 m /sec

We know that power P = force × velocity

So power = 5× 0.999 = 4.995 watt

4 0
4 years ago
A cat with a mass of 5.00 kg pushes on a 25.0 kg desk with a force of 50.0N to jump off. What is the force on the desk?
trasher [3.6K]

Answer:

i dont know

Explanation:

Sorry and good luck

3 0
3 years ago
Please help fast!! I need this in less than 17 hours!
djyliett [7]

SOLUTION is given in attachment below.

7 0
3 years ago
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