1. 1.125
2. 0.08333333333
good luck :)
Answer:
67.5feet
Step-by-step explanation:
Given parameters:
Model distance between building and gymnasium = 22.5 inches
Scale of model : 1 inch = 3 feet
Unknown:
Actual ground distance = ?
To solve this problem, we first must understand the concept of scale. A scale is a relationship that represents a dimension on a map/model compared to the true ground expression. In order to visualize or represent some real life objects on paper or in a computer, we use models. These models are an abstraction of the real world based on scales. There are different ways of representing a scale.
In this problem;
the scale is given as;
1 inch on model represents 3 feet on ground
Now, to find 22.5 inches, simply cross multiply and solve;
If 1 inch on model represents 3 feet on ground
22.5 inches on a model will be =
= 67.5feet
Therefore, the actual distance is 67.5feet
Answer:
72
Step-by-step explanation:
(24*6)/2 = 72
Answer:
jesus...you're twisted anyway 69 :)
Step-by-step explanation:
For problems like this we can use algebra to help us, the farenheight 6 hours ago was:
(2xt)-6=-20
We have to balance the sides out, first we minus 6
2xt=-26
Now we can divide by 2
t=-13
We now know the temperature 6 hours ago was -13