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Free_Kalibri [48]
3 years ago
6

A sample of polonium-210 has an initial mass of 321 milligrams (mg). If the half-life of polonium-210 is 138 days, how many mg o

f the sample remains after 1000 hours?
Chemistry
1 answer:
raketka [301]3 years ago
3 0

Hey there!

A half-life means after a certain amount of time, half of that substance will have decayed after that time.

An equation for exponential decay is the following:

y = a(1 - b)ⁿ

Where a is the original amount, b is the rate of decay, and n is time.

1000 is about 0.3 of a half life, 1000 divided by 138 days (3312 hours) is approximately 0.3.

Let's plug in values to that equation:

y = 321(1 - 0.5)^(0.3)

Simplify.

y = 260.73

There will be 260.73mg of polonium-210 remaining after 1000 hours.

Hope this helps!

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How many molecules are in 55.2g of MgBr2
Umnica [9.8K]

Answer:

Divide the given mass by its molar mass to get moles, then multiply times 6.022×1023 molecules 1 mol .

Converting between molecules and moles is done by either multiplying by or dividing by Avogadro's number:

1.To go from moles to molecules, multiply the number of moles by 6.02 x 1023.

2.To go from molecules to moles, divide the numbers of molecules by 6.02 x 1023.

We know that the number of moles is equal to the weight of the substance divided by its molar mass. Therefore, the number of moles in 19.82g of Mg is 0.81 mol.

Explanation:

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2 years ago
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Digiron [165]
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3 years ago
Which of the following molecules would be the best hydrogen bond donor?
leva [86]

Answer: Option (d) is the correct answer.

Explanation:

When a hydrogen atom comes in contact with an electronegative atom then it results in the formation of a chemical bond.

More is the electronegativity of combining atom, more stronger will be the bond with hydrogen atom. As a result, the compound formed will not easily give up hydrogen atom upon dissociation.

Whereas less is the electronegativity of atom combining with hydrogen atom, easily it will donate the hydrogen atom upon dissociation.

Since, out of the given option sulfur (S) atom has low electronegativity as compared to oxygen and nitrogen atom.

Hence, CH_{3}SH will easily donate hydrogen atom.

Thus, we can conclude that CH_{3}SH molecule would be the best hydrogen bond donor.

4 0
3 years ago
Ammonia is produced from the reaction of nitrogen and hydrogen according to the following balanced equation: N2 1 g 2 1 3H2 1 g
bekas [8.4K]

Answer:

Mass of NH3 produced = 1217 g or 1.217*10^3 g

Explanation:

<u>Given:</u>

Mass of N2 = 1.003*10^3 g

Mass of H2 = 5.003*10^2 g

<u>To determine:</u>

Maximum mass of NH3 that can be produced when the given amounts of N2 and H2 combine

<u>Calculation:</u>

The chemical reaction corresponding to the production of ammonia is:

N2(g)+3H2(g)\rightarrow 2NH3(g)

Based on the reaction stoichiometry:

1 mole of N2 combines with 3 moles of H2 to form 2 moles of NH3

moles\ of\ N2 = \frac{Mass\ N2}{Molar\ mass N2} = \frac{1.003*10^{3}g }{28g/mol} =35.8\ moles

moles\ of\ H2 = \frac{Mass\ H2}{Molar\ mass H2} = \frac{5.003*10^{2}g }{2g/mol} =250\ moles

Since the moles of N2 is less than that of H2, the limiting reagent will be N2 which would in turn determine the amount of NH3 formed.

Based on the reaction stoichiometry the N2 : NH3 ratio = 1:2

Therefore,

moles\ of\ NH3\ produced = 2*35.8 = 71.6\ moles\\\\Mass\ of\ NH3\ produced = moles*molar mass = 71.6\ moles*17\ g/mol = 1217 g

8 0
3 years ago
How many moles of KClO3 must decompose in order to produce 9 moles of oxygen gas (O2) using the following reaction by completing
mezya [45]

<u>Answer:</u> 6 moles of KClO_3 will be decomposed.

<u>Explanation:</u>

We are given:

Moles of oxygen gas produced = 9 moles

The chemical equation for the decomposition of KClO_3 follows:

2KClO_3\rightarrow 2KCl+3O_2

By the stoichiometry of the reaction:

If 3 moles of oxygen gas is produced by 2 moles of KClO_3

So, 9 moles of oxygen gas will be produced by = \frac{2}{3}\times 9=6mol of KClO_3

Hence, 6 moles of KClO_3 will be decomposed.

4 0
3 years ago
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