Answer:
Divide the given mass by its molar mass to get moles, then multiply times 6.022×1023 molecules 1 mol .
Converting between molecules and moles is done by either multiplying by or dividing by Avogadro's number:
1.To go from moles to molecules, multiply the number of moles by 6.02 x 1023.
2.To go from molecules to moles, divide the numbers of molecules by 6.02 x 1023.
We know that the number of moles is equal to the weight of the substance divided by its molar mass. Therefore, the number of moles in 19.82g of Mg is 0.81 mol.
Explanation:
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Answer: Option (d) is the correct answer.
Explanation:
When a hydrogen atom comes in contact with an electronegative atom then it results in the formation of a chemical bond.
More is the electronegativity of combining atom, more stronger will be the bond with hydrogen atom. As a result, the compound formed will not easily give up hydrogen atom upon dissociation.
Whereas less is the electronegativity of atom combining with hydrogen atom, easily it will donate the hydrogen atom upon dissociation.
Since, out of the given option sulfur (S) atom has low electronegativity as compared to oxygen and nitrogen atom.
Hence,
will easily donate hydrogen atom.
Thus, we can conclude that
molecule would be the best hydrogen bond donor.
Answer:
Mass of NH3 produced = 1217 g or 1.217*10^3 g
Explanation:
<u>Given:</u>
Mass of N2 = 1.003*10^3 g
Mass of H2 = 5.003*10^2 g
<u>To determine:</u>
Maximum mass of NH3 that can be produced when the given amounts of N2 and H2 combine
<u>Calculation:</u>
The chemical reaction corresponding to the production of ammonia is:

Based on the reaction stoichiometry:
1 mole of N2 combines with 3 moles of H2 to form 2 moles of NH3


Since the moles of N2 is less than that of H2, the limiting reagent will be N2 which would in turn determine the amount of NH3 formed.
Based on the reaction stoichiometry the N2 : NH3 ratio = 1:2
Therefore,

<u>Answer:</u> 6 moles of
will be decomposed.
<u>Explanation:</u>
We are given:
Moles of oxygen gas produced = 9 moles
The chemical equation for the decomposition of
follows:

By the stoichiometry of the reaction:
If 3 moles of oxygen gas is produced by 2 moles of
So, 9 moles of oxygen gas will be produced by =
of 
Hence, 6 moles of
will be decomposed.