Answer: 46. E 47. D 48. C 49. A
50. A 51. D 52. B 53. B 54. C
Explanation: solution attached.
Answer:
K(70°C) = 2213.376 s-1
Explanation:
balanced reaction:
- NO(g) + O3(g) → NO2(g) + O2(g)
∴ Ea = 63 KJ/mol
∴ A = 8.7 E12 s-1
∴ T = 70°C ≅ 343 K
Arrhenius eq:
∴ R = 8.314 E-3 KJ/K.mol
⇒ K(70°C) = (8.7 E12 s-1)e∧[-(63)/(8.314 E-3)(343)]
⇒ K(70°C) = (8.7 E12 s-1)*(2.5444 E-10)
⇒ K(70°C) = 2213.376 s-1
It is used as a before and after or step by step proces
Heat gained by ice cubes would be equal to the - heat lost by warm water
The moles of ice is: 50.5 g / 18.0 g/mol = 2.81 mol
Heat required to melt all of the ice is equal to: 2.81 mol X 6.02 kJ/mol = 16.9 kJ = 16890 J
Now, know whether the warm water will still be above 0C when it loses this much heat:
-1690 J = 160 g (4.184 J/gC) (Delta T) Delta T = -25C
In order to solve for the final temperature, going back to include warming of the melted ice to a final temperature:
q(ice/water) = - q(warm water)
moles (Delta Hf) + m c (T2-T1) = - m c (T2-T1)
50.5 g / 18.0 g/mol = 2.81 mol
2.81 mol X 6.02 kJ/mol + 50.5g (4.184 J/gC) (T2-0) = -160g (4.184 J/gC) ( T2-80)
16916 + 211.3T2 = -669.4 T2 + 53555
36639 = 880.7 T2
T2 = 41.6 C
