Question

How many moles of KClO3 must decompose in order to produce 9 moles of oxygen gas (O2) using the following reaction by completing the t-chart below.

Answer 1

Answer: 6 moles of $KClO_3$ will be decomposed.

Explanation:

We are given:

Moles of oxygen gas produced = 9 moles

The chemical equation for the decomposition of $KClO_3$ follows:

$2KClO_3\rightarrow 2KCl+3O_2$

By the stoichiometry of the reaction:

If 3 moles of oxygen gas is produced by 2 moles of $KClO_3$

So, 9 moles of oxygen gas will be produced by = $\frac{2}{3}\times 9=6mol$ of $KClO_3$

Hence, 6 moles of $KClO_3$ will be decomposed.