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3 years ago

Solve this 5a-d please

Mathematics

1 answer:

Talja [164]3 years ago

5 0

The answe is probably c

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Suppose x and y vary together such that y = 2 x + 11 . Suppose x varies from x = 2 to x = 8.5 .

Stells [14]

Answer:

a) x changes by 6.5 units

b) y changes by 13 units

Step-by-step explanation:

a. Over this interval, how much does x change by?

Initially, we have that x = 2.

In the end, we have that x = 8.5.

So x changes by 8.5-2 = 6.5 units

b. Over this interval, how much does y change by?

Initially, when x = 2, we have that y = 2x + 11 = 2*2 + 11 = 15

In the end, when x = 8.5, we have that y = 2*8.5 + 11 = 28

So y changes by 28 - 15 = 13 units

8 0

3 years ago

Select the correct answer

IgorLugansk [536]

Answer:

The mode would be 45.

Step-by-step explanation:

The mode is 45 because a mode is the most repeated number in a set.

8 0

3 years ago

Find the circumference of this circle<br>c,d,a,g,be

zheka24 [161]

A,G,B

IDK I think thats it

4 0

3 years ago

±√121 what is the answer

HACTEHA [7]

Answer:

±11 is the answer........

6 0

3 years ago

Read 2 more answers

A researcher wishes to estimate the number of households with two cars. How large a sample is needed in order to be 99% confiden

solmaris [256]

Answer:

Sample size n = 1382

so correct option is D) 1382

Step-by-step explanation:

given data

confidence level = 99 %

margin of error = 3%

probability = 25 %

to find out

How large a sample size needed

solution

we know here P = 25 %

so 1 - P = 1 - 0.25

1 - P = 0.75

and we know E margin of error is 0.03 so value of Z for 99%

α = 1 - 99% = 1 - 0.99

α = 0.01

and $\frac{\alpha}{2}$ = $\frac{0.01}{2}$

$\frac{\alpha}{2}$ = 0.005

so Z is here

$Z_(\frac{\alpha}{2})$ = 2.576

sample size will be

Sample size n = $(\frac{(Z_(\frac{\alpha}{2})}{E})^2 * P * (1-P)$

put here value

Sample size n = (\frac{2.576}{0.03})^2 * 0.25 * 0.75

Sample size n = 1382

so correct option is D) 1382

3 0

3 years ago