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3 years ago

HELP ME PLEASE I NEED THIS <3333

Mathematics

1 answer:

WITCHER [35]3 years ago

4 0

Answer:

214°

Step-by-step explanation:

The arc subtending an angle at the centre are equal, that is

arc ED = 90° and

arc DF = 360° - (90 + 146)° = 360° - 236° = 124°

Thus

arc EDF = arc ED + arc DF = 90° + 124° = 214°

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Natalie and her sister opened savings accounts at the same time. Natalie deposited $100 and will deposit $10 each month. Her sis

gregori [183]

Answer:

Step-by-step explanation:

Natalie

100 + 10x

Her sister

25 + 25x

Where

x = number of months

Equate Natalie and her sisters equation

100 + 10x < 25 + 25x

100 - 25 < 25x - 10x

75 < 15x

Divide both sides by 15

x < 75 / 15

x < 5

4 0

3 years ago

Sinx + siny=a<br> cosx + cosy=b<br> Find cos(x+y/2)

romanna [79]

Using the addition rule of the Sine function and the Cosine function, we obtain $\cos\dfrac{x+y}{2}=\dfrac{b}{\sqrt{a^2+b^2}}$ .

<h3>What are the formulas for (sin x + sin y) and (cos x + cos y)?</h3>

The formula for the addition of two Sine functions ( $\sin x+\sin y$ ) is $\sin x + \sin y = 2\sin\frac{x+y}{2}\cos\frac{x-y}{2}$ .
The formula for the addition of two Cosine functions ( $\cos x+\cos y$ ) is $\cos x + \cos y = 2\cos\frac{x+y}{2}\cos\frac{x-y}{2}$ .

Given that

$\sin x + \sin y = a\\\cos x + \cos y = b$

Then using the above formulas, we get:

$2\sin\frac{x+y}{2}\cos\frac{x-y}{2}=a$ (1)

$2\cos\frac{x+y}{2}\cos\frac{x-y}{2}=b$ (2)

Dividing the equation (1) by (2), we get:

$\dfrac{\sin\dfrac{x+y}{2}}{\cos\frac{x-y}{2}}=\dfrac{a}{b}\\\Longrightarrow \tan\dfrac{x+y}{2}=\dfrac{a}{b}$ (3)

Now, we know that $\cos\theta=\dfrac{1}{\sqrt{1+\tan^2\theta}}$ .

Thus, using the above formula, we get from (3):

$\cos\dfrac{x+y}{2}=\dfrac{1}{\sqrt{1+\tan^2\dfrac{x+y}{2}}}\\\Longrightarrow \cos\dfrac{x+y}{2}=\dfrac{1}{\sqrt{1+\dfrac{a^2}{b^2}}}\\\Longrightarrow \cos\dfrac{x+y}{2}=\dfrac{b}{\sqrt{a^2+b^2}}$

Therefore, using the addition rule of the Sine function and the Cosine function, we obtain $\cos\dfrac{x+y}{2}=\dfrac{b}{\sqrt{a^2+b^2}}$ .

To know more about Sine and Cosine functions, refer: brainly.com/question/27728553

#SPJ9

3 0

2 years ago

What are the domain and range of each relation?

marusya05 [52]

Answer:i cant see it that well its blurry

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

In a typical week you drive 34.85 km on Monday, 28.23 km on

Tasya [4]

Answer:

63.08 km

Step-by-step explanation:

To find how far you drive, add up the km from only Monday and Tuesday, since you aren't driving on Friday

34.85 + 28.23

= 63.08

So, you would drive 63.08 km

6 0

3 years ago

What is the solution to this equation ?<br><br><br> x + 9 = -4

PolarNik [594]

Isolate the x. Note the equal sign. What you do to one side, you do to the other.

Subtract 9 from both sides

x + 9 (-9) = -4 (-9)

x = -4 - 9

x = -13

-13 is your solution

hope this helps

8 0

4 years ago