1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vichka [17]
3 years ago
6

A particle with charge − 2.74 × 10 − 6 C −2.74×10−6 C is released at rest in a region of constant, uniform electric field. Assum

e that gravitational effects are negligible. At a time 6.36 s 6.36 s after it is released, the particle has a kinetic energy of 6.65 × 10 − 10 J. 6.65×10−10 J. At what time t t after the particle is released has it traveled through a potential difference of 0.351 V
Physics
1 answer:
s2008m [1.1K]3 years ago
6 0

Answer:

241.7 s

Explanation:

We are given that

Charge of particle=q=-2.74\times 10^{-6} C

Kinetic energy of particle=K_E=6.65\times 10^{-10} J

Initial time=t_1=6.36 s

Final potential difference=V_2=0.351 V

We have to find the time t after that the particle is released and traveled through a potential difference 0.351 V.

We know that

qV=K.E

Using the formula

2.74\times 10^{-6}V_1=6.65\times 10^{-10} J

V_1=\frac{6.65\times 10^{-10}}{2.74\times 10^{-6}}=2.43\times 10^{-4} V

Initial voltage=V_1=2.43\times 10^{-4} V

\frac{\initial\;voltage}{final\;voltage}=(\frac{initial\;time}{final\;time})^2

Using the formula

\frac{V_1}{V_2}=(\frac{6.36}{t})^2

\frac{2.43\times 10^{-4}}{0.351}=\frac{(6.36)^2}{t^2}

t^2=\frac{(6.36)^2\times 0.351}{2.43\times 10^{-4}}

t=\sqrt{\frac{(6.36)^2\times 0.351}{2.43\times 10^{-4}}}

t=241.7 s

Hence, after 241.7 s the particle is released has it traveled through a potential difference of 0.351 V.

You might be interested in
The first asteroid to be discovered is Ceres. It is the largest and most massive asteroid in our solar system’s asteroid belt, h
stira [4]

Answer:

4.81*10^{29}J

Explanation:

Since the formula for kinetic energy of an object is:

E_k = \frac{mv^2}{2}

Where m is the mass of the object and v is the speed. We can substitute m = 3*10^{21}kg and v = 17900m/s:

E_k = \frac{3*10^{21} * (17900)^2}{2} = 4.81*10^{29}J

3 0
2 years ago
A compound machine is sued to lift a car. If you apply a force of 60 N to the machine, it lifts the car with a force of 550 N.
mrs_skeptik [129]

a) MA=550/60=9.17

b) Wu=1150*0.35=402.5 J

3 0
2 years ago
Read 2 more answers
The water in a river flows uniformly at a constant speed of 2.50 m/s between parallel banks 80.0 m apart. You are to deliver a p
NISA [10]

Answer:

a)  The swimmer should travel perpendicular to the bank to minimize the spent in getting to the other side.

b) 133.33 m

c) 53.13°

d) 106.67 m

Explanation:

a) The swimmer should travel perpendicular to the bank to minimize the spent in getting to the other side.

b) velocity = distance * time

Let the velocity of the swimmer be v_{s} = 1.5 m/s

The separation of the two sides of the river, d = 80 m

The time taken by the swimmer to get to the other end of the river bank,

t = \frac{d}{v_{s} }

t = 80/1.5

t = 53.33 s

The swimmer will be carried downstream by the river through a distance, s

Let the velocity of the river be v_{r} = 2.5 m/s

S = v_{r} t

S = 53.33 * 2.5

S = 133.33 m

c) To minimize the distance traveled by the swimmer, his resultant velocity must be perpendicular to the velocity of the swimmer relative to water

That is ,

cos \theta = \frac{v_{s} }{v_{r} } \\cos \theta = 1.5/2.5\\cos \theta = 0.6\\\theta = cos^{-1} 0.6\\\theta = 53.13^{0}

d) Downstream velocity of the swimmer, v_{y} = v_{s} sin \theta\\

v_{y} = 1.5 sin 53.13\\v_{y} = 1.2 m/s

The vertical displacement is given by, y = v_{y} t

80 = 1.2 t

t = 80/1.2

t = 66.67 s

the horizontal speed,

v_{x} = 2.5 - 1.5cos53.13\\v_{x} = 1.6 m/s

The downstream horizontal distance of the swimmer, x = v_{x} t

x = 1.6 * 66.67

x = 106.67 m

7 0
3 years ago
A ball is rolled uphill a distance of 12 meters before it slows, stops, and begins to roll back. The ball rolls downhill 20 mete
Sedaia [141]
The ball rolled a distance of
d = 12m + 20m.
But the change of position is
x = + 12m - 20m
5 0
3 years ago
Which statement is supported by this scenario?
Temka [501]

Answer:

For Yanni, the speed of the ball is 15 m/s, and for the quarterback, the speed of the ball is 8 m/s.

Explanation:

6 0
2 years ago
Read 2 more answers
Other questions:
  • Reaction rate depends on how many molecules come into contact with each other with enough energy to react. How would you increas
    6·1 answer
  • Which most likely has the greatest conductivity?
    14·2 answers
  • A bike moves. 50 m in 10 seconds calculate the speed of the bike
    13·1 answer
  • A student buys a 5000 Btu window air conditioner for his apartment bedroom. He monitors it for one hour on a hot day and determi
    12·1 answer
  • What is the name of NASA's special plane?
    14·1 answer
  • How does inertia affect the motion of an object?
    11·1 answer
  • In which layer of Earth’s interior does convection occur?
    7·2 answers
  • Getyour pointsssssssssssssssssssssss
    9·2 answers
  • What is gravitonal force
    15·1 answer
  • a steam engine works on its vicinity and 285 k heat is released with the help of 225 degree centigrade energy absorbed to the sy
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!