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Artyom0805 [142]
3 years ago
7

A particle moves along a circle with radius R, so that the tangential component of its acceleration is constant. At t = 0 the ve

locity of the particle was equal to zero. Find
(a) the normal component an of the acceleration as function of time.
(b) the magnitude of the acceleration vector a as well as the angle the vector a forms with the position vector r as functions of time.
Physics
1 answer:
Gala2k [10]3 years ago
7 0
Answer: a


Explanation:
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A car advertisement states that a certain car can accelerate from rest to 140 m/s in 7 seconds. Find the car’s average accelerat
4vir4ik [10]

Answer:

<h2>20 m/s</h2>

Explanation:

Bc Accelerations formula is V/T (velocity over time).

with this you can plug in the velocity witch is just speed with direction over time witch looks like this 140 m/s / 7 s.

and when you calculate acceleration= 20 m/s

Plz give brainliest:-)

6 0
3 years ago
An elevator is pulled up by a cable with a force of 65,000 N. The upward acceleration of the elevator is 1.8 m/s/s. What is the
goblinko [34]

Answer:

36111 kg

Explanation:

Given

Force = 65000N

Acceleration = 1.8m/s²

Required

Determine the mass of the elevator

This question will be answered using the following Force formula.

Force = Mass * Acceleration

Substitute values for Force and Acceleration

65000N = Mass * 1.8m/s²

Make Mass the subject

Mass = 65000N/1.8m/s²

Mass = 36111.11 kg

From the list of given options, option E answers the question.

6 0
3 years ago
Definition of definite​
KIM [24]

Google definition: a statement of the exact meaning of a word, especially in a dictionary.

the degree of distinctness in outline of an object, image, or sound, especially of an image in a photograph or on a screen.

My definition: The meaning or deintion of any word.

5 0
4 years ago
Woman has a near point of 75.0 cm. What focal length, f, is necessary for the corrective lens so that he can hold his physics bo
Komok [63]

Answer:

The focal length of the lens must be 27.3cm

Explanation:

Image distance= -75 cm

Object distance= 20.0cm

From:

1/v + 1/u = 1/f

-1/75+ 1/20 = 1/f

11/300= 1/f

f= 300/11

f= 27.3cm

The focal length of the lens must be 27.3cm

8 0
3 years ago
A spring of force constant 285.0 N/m and unstretched length 0.230 m is stretched by two forces, pulling in opposite directions a
Kaylis [27]

Answer: W = 0.3853 J, e = 0.052 m

Explanation: Given that,

K =285.0N/M , L = 0.230m , F = 15N , e = ?

F = Ke

15 = 285 × e

e = 15÷ 285

e =0.052 m

e + L = 0.052 + 0.230

= 0.282m ( spring new length )

Work needed to stretch the spring

W = 1/2ke2

W = 1/2 × 285 x 0.052 × 0.052

W = 0.3853 J

8 0
3 years ago
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