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Artyom0805 [142]
3 years ago
7

A particle moves along a circle with radius R, so that the tangential component of its acceleration is constant. At t = 0 the ve

locity of the particle was equal to zero. Find
(a) the normal component an of the acceleration as function of time.
(b) the magnitude of the acceleration vector a as well as the angle the vector a forms with the position vector r as functions of time.
Physics
1 answer:
Gala2k [10]3 years ago
7 0
Answer: a


Explanation:
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The ceiling of a large symphony hall is covered with acoustic tiles which have small holes that are 4.35 mm center to center. If
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Answer:

The distance between their eye and the ceiling is 33.06 m.

Explanation:

Given that,

The ceiling of a large symphony hall is covered with acoustic tiles which have small holes that are 4.35 mm center to center, D = 4.35 mm

Diameter of the eye of pupil, d = 5.1 mm

Wavelength, \lambda=550\ nm

We need to find the distance between their eye and the ceiling. Using Rayleigh criteria, we get the distance as follows :

L=\dfrac{Dd}{1.22\lambda}\\\\L=\dfrac{4.35\times 10^{-3}\times 5.1\times 10^{-3}}{1.22\times 550\times 10^{-9}}\\\\L=33.06\ m

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3 0
3 years ago
N in-ground swimming pool has the dimensions shown in the drawing. It is filled with water to a uniform depth of 3.00 m. The den
Doss [256]

Answer:

The pressure is  P = 1.31*10^{5} \ Pa

Explanation:

From the question we are told that

    The depth of the swimming pool is  d =  3.00 \  m

     The density of water is  \rho = 1.00*10^{3} \  kg /m^3

Generally the  total pressure exerted on the bottom of the swimming pool is mathematically represented as

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So

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=>     P = 130725 \ Pa

=>    P = 1.31*10^{5} \ Pa

     

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3 years ago
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