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3 years ago

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A 0.26-kg rock is thrown vertically upward from the top of a cliff that is 32 m high. when it hits the ground at the base of the

cliff, the rock has a speed of 30 m/s .

1 answer:

Elanso [62]3 years ago

7 0

this is your teacher get off your phone

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Voltage has been described as similar to the water in the water pipes in your home. What other analogy can you think of that is

jeka94

Answer:

how im i suopose to iowi

Explanation:

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3 0

3 years ago

A bowling ball weighing 71.7 N is attached to the ceiling by a rope of length 3.73 m . The ball is pulled to one side and releas

vekshin1

Answer:

A) a = 5.673 m/s²

The direction will be upwards vertically towards the point where it is suspended.

B) T = 113.2 N

Explanation:

A) We are given;

Weight of bowling ball; W = 71.7 N

Speed; v = 4.6 m/s

Rope length; r = 3.73 m

Now, formula for the centripetal acceleration is;

a = v²/r

Thus; a = 4.6²/3.73

a = 5.673 m/s²

The direction will be upwards vertically towards the point where it is suspended.

B) since weight is 71.7 N, it means that;

Mass = weight/acceleration = 71.7/9.8

Mass(m) = 7.316 kg

Thus,

Centripetal force is;

F_cent = 7.316 × 5.673

F_cent = 41.5 N

Thus, Tension in the rope is;

T = W + F_cent

T = 71.7 + 41.5

T = 113.2 N

4 0

3 years ago

You use 35j of energy to move a 7n object. How far did you move it ?

musickatia [10]

5m

Explanation:

Given parameters:

Energy = 35J

Force on object = 7N

Unknown:

Distance moved = ?

Solution:

The energy on the car will cause the car to do work . When work is done, a force moves a body in particular distance. We can see that energy and force are related:

Energy = force x distance

Distance = $\frac{Energy}{force}$

Inputting the parameters:

Distance = $\frac{35}{7}$ = 5m

Learn more:

Work done brainly.com/question/9100769

#learnwithBrainly

8 0

4 years ago

A spring-loaded toy gun is used to shoot a ball of mass 1.5 kg straight up in the air, as shown. The spring has spring constant

asambeis [7]

Answer:

Part a)

U = 15.5 J

Part b)

h = 1.05 m

Part c)

v = 4.55 m/s

Explanation:

Part a)

Initial potential energy stored in the spring is given by

$U = \frac{1}{2}kx^2$

now we have

$k = 777 N/m$

x = 20.0 cm

now from above formula we will have

$U = \frac{1}{2}(777)(0.20)^2$

$U = 15.5 J$

Part b)

By mechanical energy conservation law we can say that initial spring potential energy stored = final gravitational potential energy at the top position

$\frac{1}{2}kx^2 = mgh$

$15.5 = 1.5(9.8)h$

$h = 1.05 m$

So maximum height from gun is 1.05 m

Part c)

For muzzle velocity of the ball we can use the energy conservation again

According to which the final kinetic energy of the ball = initial spring energy stored in it

$\frac{1}{2}mv^2 = \frac{1}{2}kx^2$

$(\frac{1}{2})(1.5 v^2) = 15.5$

$v = v = 4.55 m/s$

4 0

3 years ago

What is the anomalous expansivity of water

salantis [7]

Answer:

The anomalous expansion of water is an abnormal property of water whereby it expands instead of contracting when the temperature goes from 4°C to 0°C, and it becomes less dense. The density becomes less and less as it freezes because molecules of water normally form open crystal structures when in solid form.

7 0

3 years ago