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natta225 [31]
3 years ago
10

A 0.26-kg rock is thrown vertically upward from the top of a cliff that is 32 m high. when it hits the ground at the base of the

cliff, the rock has a speed of 30 m/s .
Physics
1 answer:
Elanso [62]3 years ago
7 0

this is your teacher get off your phone

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An unknown mass is on a flat frictionless surface and a 2 kg object is attached to it with a string going over pulleyt mounted t
Lynna [10]

Answer:

Explanation:

F=ma

F in this case is the gravity acting on the 2kg object. Acceleration of gravity is 9.8 m/s^2. SF=ma, so

F = 2kg*(9.8 m/s^2) = 19.6 N

Now use this force to determine the mass of the object on the table:

F=ma

19.6 N (1N=kg*m/s^2) = m*(1.8 m/s^2)

m = 10.89 kg

3 0
3 years ago
A uniform disk is constrained to rotate about an axis passing through its center and perpendicular to the plane of the disk. If
katrin2010 [14]

A uniform disk is constrained to rotate about an axis passing through its center and perpendicular to the plane of the disk. If the disk starts from rest and is then brought in contact with a spinning rubber wheel, we observe that the disk gradually begins to rotate too. If after 35 s of contact with this spinning rubber wheel, the disk has an angular velocity of 4.0 rad/s, find the average angular acceleration that the disk experiences. (Assume the positive direction is in the initial direction of rotation of the disk. Indicate the direction with the sign of your answer.)

Assume after 35 s of contact with this spinning rubber wheel, the disk has an angular velocity of 11.0 rad/s.

Answer:

385 rad

Explanation:

The expression for the angular acceleration of a disk that is in contact with a spinning wheel can be given as:

\alpha = \frac{\delta \omega}{\delta t}

where \delta\omega = \omega_f - \omega_i

\alpha = \frac{ \omega_f-\omega_i}{\delta t}

\alpha = \frac{ 4.0 rad/s-0 rad/s}{35}

\alpha =0.14 rad/s^2

Angular displacement of a disk can be calculated by using the formula:

\theta = \omega t

substituting 11.0 rad/s for \omega and t = 35 s ; we have:

\theta = 11.0 rad/s * 35 s

\theta = 385 rad

4 0
3 years ago
Read 2 more answers
Examine the scenario.
vovangra [49]

Answer:

acceleration 8 km/h/s south

Explanation:

First of all, let's remind that a vector quantity is a quantity which has both a magnitude and a direction.

Based on this definition, we can already rule out the following two choices:

distance: 40 km

speed: 40 km/h

Since they only have magnitude, they are not vectors.

Then, the following option:

velocity: 5 km/h north

is wrong, because the car is moving south, not north.

So, the correct choice is

acceleration 8 km/h/s south

In fact, the acceleration can be calculated as

a=\frac{v-u}{t}

where

v = 40 km/h is the final velocity

u = 0 is the initial velocity

t = 5 s is the time

Substituting,

a=\frac{40 km/h-0}{5 s}=8 km/h/s

And since the sign is positive, the direction is the same as the velocity (south).

7 0
4 years ago
I don’t know if I did these rights someone check them or give me the answers? I know the photo has some stuff cut off but you ca
Nana76 [90]

I can’t read some of your work

3 0
3 years ago
1. Classify What type of heat transfer occurs
valentina_108 [34]
Convection because I’m in seventh grade
5 0
3 years ago
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