Answer:
The correct answer is D. 3x² - x + 3
Step-by-step explanation:
4x² - x + 6 - (x² + 3)
= 4x² - x² - x + 6 - 3
= 3x² - x + 3
Use the Pythagorean theorem. The equation for this right triangle would be a^2+b^2=c^2. Since you have one leg and the hypotenuse, you can plug these into the equation. It would be 7^2+b^2=12^2. Do the exponents. You will get 49+b^2=144. You need to get b by itself so subtract each side by 49. You get the equation b^2=95. Square root each side to get b=9.746. This rounds to 9.7. So the answer is A. Hope this helps! ;)
Let x be the 1st odd number, and x+2 the second odd consecutive number:
(x)(x + 2) = 6[((x) + (x+2)] -1
x² + 2x = 6(2x + 2) - 1
x² + 2x = 12x +12 - 1
And x² - 10x - 11=0
Solve this quadratic expression:
x' = [+10 +√(10²- 4.(1)(-11)]/2 and x" = [+10 -√(10²- 4.(1)(-11)]/2
x' = [10 + √144]/2 and x" = [10 - √64]/2
x' = (10+12)/2 and x" = (10-12)/2
x = 11 and x = -1
We have 2 solutions that satisfy the problem:
1st for x = 11, the numbers at 11 and 13
2nd for x = - 1 , the numbers are -1 and +1
If you plug each one in the original equation :(x)(x + 2) = 6[((x) + (x+2)] -1
you will find that both generates an equlity
<span>The answer is 454. Since the value of the ones digit is 4, the last digit is a 4. Next, since the ones digit is the same as the hundreds digit, the first digit would be 4. Finally, the middle digit is the tens place and would be 5 since the tens digit is 50.</span>