(X^4)(3x^3-2)(4x^2+5x)

1 answer:

5 0

Answer:

Step-by-step explanation:

$x^4(3x^3-2)(4x^2+5x)\\=x^4(12x^5+15x^4-8x^2-10x)\\=12x^9+15x^8-8x^6-10x^5$

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k0ka [10]

<span>342 u have to subtract to get this answer</span>

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Rudik [331]

It would also be 42 because the triangle is divided in half.

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Furkat [3]

$\frac{45+19}{2} =\frac{64}{2} =32$

The average of 45 and 19 is 32.

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lbvjy [14]

X1 = 1.71429
X2 = 3.4

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yuradex [85]

Answer:

c because if you subtract

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2 years ago