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Ksju [112]
3 years ago
13

(X^4)(3x^3-2)(4x^2+5x)

Mathematics
1 answer:
Tresset [83]3 years ago
5 0

Answer:

Step-by-step explanation:

x^4(3x^3-2)(4x^2+5x)\\=x^4(12x^5+15x^4-8x^2-10x)\\=12x^9+15x^8-8x^6-10x^5

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What is the radius and center of (y-7)^2=25-(x-3)^2
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If f(x) = x and g(x) = 2x + 7, what is<br>f[90X)] when g(x) = 11?​
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You are purchasing an exercise machine for a physical therapy office. The machine has a 20 inch vertical space where you add wei
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3 years ago
Find the 6th term of the arithmetic sequence X – 9, -X – 11, -3.3 – 13, ...
MrMuchimi

Answer:

-13x-23

Step-by-step explanation:

Given sequence:  x-9, -x-11, -3x-13

Therefore,

  • a_1=x-9
  • a_2=-x-11
  • a_3=-3x-13

General form of an arithmetic sequence: a_n=a+(n-1)d

(where a is the first term and d is the common difference)

To find the common difference, subtract a term from the next term:

\begin{aligned}d & =a_2-a_1\\ & =(-x-11)-(x-9)\\ & = -x-11-x+9\\ & = -2x-2\end{aligned}

Therefore,

a_n & =(x-9)+(n-1)(-2x-2)

To find the 6th term, input n = 6 into the equation:

\begin{aligned}\implies a_6 & =(x-9)+(6-1)(-2x-2)\\ & = (x-9)+7(-2x-2)\\ & = x-9-14x-14\\ & = -13x-23\end{aligned}

3 0
2 years ago
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