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Ksju [112]
2 years ago
13

(X^4)(3x^3-2)(4x^2+5x)

Mathematics
1 answer:
Tresset [83]2 years ago
5 0

Answer:

Step-by-step explanation:

x^4(3x^3-2)(4x^2+5x)\\=x^4(12x^5+15x^4-8x^2-10x)\\=12x^9+15x^8-8x^6-10x^5

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The Expression 4x^2-p(x)+7 leaves a remainder of -2 when divided by (x-3) find the value of p
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Answer:

(c)  For p = 15,  4x^2-p(x)+7 leaves a remainder of -2 when divided by (x-3).

Step-by-step explanation:

Here,  The dividend expression is  4x^2-p(x)+7 = E(x)

The Divisor = (x-3)

Remainder  = -2

Now, by <u>REMAINDER THEOREM</u>:

Dividend  = (Divisor x Quotient)  + Remainder

If ( x -3 ) divides the given polynomial with a remainder -2.

⇒  x = 3  is a  solution of given polynomial E(x)  - (-2) =  

E(x)  - (-2)  = 4x^2-p(x)+7 -(-2)  = 4x^2-p(x)+9 =  S(x)

Now, S(3) = 0

⇒4x^2-p(x)+9 = 4(3)^2 - p(3) + 9 = 0\\\implies 36 - 3p + 9 = 0\\\implies 45= 3p , \\or p  =15

or, p =1 5

Hence, for p = 15,  4x^2-p(x)+7 leaves a remainder of -2 when divided by (x-3).

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