Until now, given a function <span>f(x)</span>, you would plug a number or another variable in for x. You could even get fancy and plug in an entire expression for x. For example, given <span>f(x) = 2x + 3</span>, you could find <span>f(y2 – 1)</span> by plugging<span> y2 – 1</span> in for x to get <span>f(y2 – 1) = 2(y2 – 1) + 3 = 2y2 – 2 + 3 = 2y2 + 1</span>.
In function composition, you're plugging entire functions in for the x. In other words, you're always getting "fancy". But let's start simple. Instead of dealing with functions as formulas, let's deal with functions as sets of<span> (x, y)</span><span> points </span>
<span>Hope this awnsers your question</span>
<span>
</span>
<span />
1 m = 100 cm
800 m = 800 x 100 = 80000 cm
Therefore, 800 m 35 cm = 80000 cm + 35 cm = 80035 cm
Also, 154 m = 154 x 100 = 15400 cm
Therefore, 154 m 49 cm = 15449 cm
Therefore, <span>800m 35cm - 154m 49cm = 80035 cm - 15449 cm = 64586 cm = 645m 86cm</span>
Answer:
whts the question??
Step-by-step explanation:
Answer:
C(x)=25x+6000
b=2250
Step-by-step explanation:
C(x)=mx+b
m-marginal cost
x-no items
finding B
C(x)mx+b
6000=25(130)+b
b=2250
General substitution
C(x)=25x+6000
