Distribute
3x+6>0
Subtract 6 from both sides
3x>-6
Divide both sides by 3
x>-2
Final answer: x>-2

![{3}^{8 \frac{1}{4} x} \\ = {3}^{8} \times {3}^{ \frac{1}{4}x } \\ = {3}^{8} \times \sqrt[4x]{3}](https://tex.z-dn.net/?f=%7B3%7D%5E%7B8%20%5Cfrac%7B1%7D%7B4%7D%20x%7D%20%20%5C%5C%20%20%3D%20%20%7B3%7D%5E%7B8%7D%20%20%5Ctimes%20%20%7B3%7D%5E%7B%20%5Cfrac%7B1%7D%7B4%7Dx%20%7D%20%20%5C%5C%20%20%3D%20%20%7B3%7D%5E%7B8%7D%20%20%5Ctimes%20%20%5Csqrt%5B4x%5D%7B3%7D%20)
I cannot see the choices, but here are a couple solutions, depending on what you meant.
Answer:
Step-by-step explanation:

Depends on where the x is. If in the equilateral triangle, x is the only angle missing then you do whatever two numbers they gave + x = 180 then solve.
If it’s in an isosceles and it’s the same situation, you do x = the side with the same amount of degrees (you will know because there will be a line on the “x” and given side