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3 years ago

Please help don’t get it

Mathematics

1 answer:

posledela3 years ago

5 0

Answer:

Step-by-step explanation:

Whenever you are asked to find the number of square feet covered by something, you are finding an area. To find the area of Jason’s circle, you first need to figure out if you have been given the radius or the diameter. By definition, the diameter of a circle is the longest distance across the circle, so we know here that the diameter is 8 feet. This means that the radius is 4 feet. So...

A = π(4)2

= 16π

≈ 50.2 square feet

So, Jason’s circle will cover about 50.2 square feet of his wall (and B is the closest one to that)

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Which of the following values has 3 significant figures?

Wittaler [7]

Answer: D. al of the above

Step-by-step explanation:

the numbers 1-7 are the significant figures, and if there is a zero but still three numbers ranging from 1-7, it counts

4 0

2 years ago

Read 2 more answers

How do I solve this problem?

Andrews [41]

so the line is dog so we know the full line is 60 units long. The 2 parts (do and og) add up to the full length so we can make the equation:

(4x-3)+(2x+21)=60

6x+18=60

6x=42

x=7

if you need to fine do or og, just plug in x to its equation

6 0

3 years ago

Three times as many children as adults attended a concert on Saturday. An adult ticket cost $7 and a child’s ticket cost $3. The

Ierofanga [76]

For this case we propose a system of equations:

x: Let the variable representing the number of children in the concert

y: Let the variable representing the number of adults at the concert

According to the assistance we have:

$x = 3y$

According to the cost we have:

$3x + 7y = 6000$

Substituting the first in the second equation we have:

$3 (3y) + 7y = 6000\\9y + 7y = 6000\\16y = 6000\\y = \frac {6000} {16}\\y = 375$

Thus, the concert was 375 adults.

On the other hand we have:

$x = 3 (375) = 1125$

Thus, the concert was 1125 children.

In total they were:

$375 + 1125 = 1500$ people

ANswer:

The concert was 1500 people

3 0

3 years ago

A bucket that weighs 6 lb and a rope of negligible weight are used to draw water from a well that is 80 ft deep. The bucket is f

zaharov [31]

Answer:

3200 ft-lb

Step-by-step explanation:

To answer this question, we need to find the force applied by the rope on the bucket at time $t$

At $t=0, the weight of the bucket is 6+36=42 \mathrm{lb}$

After $t$ seconds, the weight of the bucket is $42-0.15 t \mathrm{lb}$

Since the acceleration of the bucket is the force on the bucket by the rope is equal to the weight of the bucket.

If the upward direction is positive, the displacement after $t$ seconds is $x=1.5 t$

Since the well is 80 ft deep, the time to pull out the bucket is $\frac{80}{2}=40 \mathrm{~s}$

We are now ready to calculate the work done by the rope on the bucket.

Since the displacement and the force are in the same direction, we can write

$W=\int_{t=0}^{t=36} F d x$

Use $x=1.5 t$ and $F=42-0.15 t$

$W=\int_{0}^{36}(42-0.15 t)(1.5 d t)$

$=\int_{0}^{36} 63-0.225 t d t$

$=63 \cdot 36-0.2 \cdot 36^{2}-0=3200 \mathrm{ft} \cdot \mathrm{lb}$

$=\left[63 t-0.2 t^{2}\right]_{0}^{36}$

$W=3200 \mathrm{ft} \cdot \mathrm{lb}$

4 0

2 years ago

Read the problem and solve.

gavmur [86]

442 is the answer thedjfbbxhcbdhx

8 0

2 years ago