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alexandr1967 [171]
3 years ago
10

Calculate the surface area of a triangular prism. It has an isosceles triangle face with a base of 4 m and a height of 3 m. The

length of the prism is 9 m.

Mathematics
1 answer:
son4ous [18]3 years ago
4 0

Answer:

48 + 18√13 cm²

Step-by-step explanation:

HC = BC/2 = 4m/2 = 2 m

AC = √AH² + HC² = √9 + 4 = √13

A = 2×A(ABC) + 2×A(ACFD) + A(BCFE)

= 2×AH×BC/2 + 2×AC×CF + BC×CF

= 2×3×4/2 + 2×√13×9 + 4×9

=12 + 18√13 + 36

= 48 + 18√13 cm²

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givi [52]

Answer:

1/8 of a sandwich

3 0
3 years ago
Read 2 more answers
Plzzzzz help
ololo11 [35]

Answer:

D. 0.343

Step-by-step explanation:

You can see the first three options as 0.340 so if you substract this number with 0.343 the remainder is positive 3.

This strategy also can be applied to the number 0.3409 but in this occasion the result is different:

0.343 - 0.3409 = 2.1\times 10^{-3}

That is small number but still is positive that's meaning that between 0.343 and 0.3409 the greatest value is 0.343 .

6 0
2 years ago
Can someone please help me out! and please explain your answer, and how you got it right! thank you so much!
Contact [7]

It is

24x - 30

The equation for area of a trapezoid is

\frac{1}{2} (a + b) \times h

Substituting our values in

\frac{1}{2} (3x + 7 + 5x - 3) \times 6

We can then simplify the expression

\frac{1}{2} (8x - 10) \times 6 \\ (4x - 5) \times 6 \\ 24x - 30

8 0
3 years ago
A rope of length 18 feet is arranged in the shape of a sector of a circle with central angle O radians, as shown in the
creativ13 [48]

Answer:

A(\theta)=\frac{162 \theta}{(\theta+2)^2}

Step-by-step explanation:

The picture of the question in the attached figure

step 1

Let

r ---> the radius of the sector

s ---> the arc length of sector

Find the radius r

we know that

2r+s=18

s=r \theta

2r+r \theta=18

solve for r

r=\frac{18}{2+\theta}

step 2

Find the value of s

s=r \theta

substitute the value of r

s=\frac{18}{2+\theta}\theta

step 3

we know that

The area of complete circle is equal to

A=\pi r^{2}

The complete circle subtends a central angle of 2π radians

so

using proportion find the area of the sector by a central angle of angle theta

Let

A ---> the area of sector with central angle theta

\frac{\pi r^{2} }{2\pi}=\frac{A}{\theta} \\\\A=\frac{r^2\theta}{2}

substitute the value of r

A=\frac{(\frac{18}{2+\theta})^2\theta}{2}

A=\frac{162 \theta}{(\theta+2)^2}

Convert to function notation

A(\theta)=\frac{162 \theta}{(\theta+2)^2}

6 0
4 years ago
NEED THE ANSWER ASAP
quester [9]
Not 100% sure this is right but
60cm^2
8 0
3 years ago
Read 2 more answers
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