Answer:
2.34 %
Explanation:
Since the density of the Jello, ρ = 1.14 g/mL and ρ = m/v where m = mass of jello and v = volume of jello = 475 mL.
So, m = ρv
substituting the values of the variables into the equation, we have
m = ρv
m = 1.14 g/mL × 475 mL = 541.5 g
Since we have 13 g of sugar in the jello, the total mass present is 13 g + 541.5 g = 554.5 g
So, the percentage by mass of sugar present % m/m = mass of sugar present/total mass × 100 %
= 13 g/554.5 g × 100 %
= 0.0234 × 100 %
= 2.34 %
So, the percentage by mass of sugar present % m/m = 2.34 %
The elements have the same number of electrons in the outer ring so they react with the same substances
Answer: 10. 39.7 g
11. 650 g of
Explanation:
To calculate the moles, we use the equation:
a) moles of
According to stoichiometry :
2 moles of produce = 1 mole of
Thus 2.5 moles of produce= of
Mass of
Thus 39.7 g of will be produced from 5.0 g of hydrogen.
11.
According to stoichiometry :
1 mole of is produced by = 2 moles of
Thus 1.50 moles of are produced by = of
Mass of
Thus 650 g of woukd be decomposed to produce 1.5 mol of oxygen
It is not important to accurately measure the amount of HCl placed in the eudiometer tube since HCl will be added in excess to react with all the moles of Mg.
In gas stoichiometry, through the method of displacement of a liquid (generally water), the gaseous byproduct is collected inside a long, thin graded glass tube called a eudiometer.
If we consider a reaction between Magnesium and Hydrochloric acid to give a product known as magnesium chloride and hydrogen gas, we can have the chemical equation represented as:
From the above reaction, for each mole of Magnesium taking place in the reaction, 1 mole of hydrogen gas is also produced.
Thus, we can have a prediction that HCl can always be added in excess in order for us to react to all the moles of solid magnesium, hence, it is not important to measure the moles of HCl since it will be added in excess.
Learn more about gas stoichiometry here:
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