Moles of P = 56,4g/30,974g/mole = 1,82 moles P
moles of O = 43,6/15,999 = 2,73 moles of O
converting to the simplest ratio:
For P : 1,82/1,82 = 1
For O : 2,73/1,82 = 1,5
1 P and 2 oxygens.
PO2 -> the empirical formula
hope this help
Answer:
102.26 moles of helium were required to Fill the Goodyear Blimp
Explanation:
To solve this question we need to use combined gas law:
PV = nRT
<em>Where P is pressure, V is volume of gas (2500L), n are moles of gas (Our incognite), R is gas constant (0.082atmL/molK) and T is absolute temperature</em>
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Assuming atmospheric condition we can write P = 1atm and T = 25°C = 298.15K
Replacing:
PV/RT = n
1atm*2500L / 0.082atmL/molK*298.15K = n
<h3>102.26 moles of helium were required to Fill the Goodyear Blimp</h3>
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