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MaRussiya [10]
3 years ago
15

A 100.0 mL sample of a 0.200 M aqueous solution of K2CrO4 was added to 100.0 mL of a 0.100 M aqueous solution of BaCl2. The mixt

ure was stirred and the precipitate was collected, dried carefully, and weighed. How many grams of precipitate should be obtained? The reaction is shown below: K2CrO4(aq) + BaCl2(aq) ď‚® BaCrO4(s) + 2 KCl(aq) A. 2.05 g B. 2.53 g C. 5.07 g D. 6.16 g E. 7.60 g
Chemistry
1 answer:
stepan [7]3 years ago
5 0
The correct answer is 2.53 g of precipitate, BaCrO4.

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