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Crank
3 years ago
11

What substance is added during hydrolysis in order to break down food macromolecules?

Chemistry
2 answers:
TEA [102]3 years ago
3 0
Hey there! :D

Look at the word hydrolysis. Hydro= water Lysis = split. (Root words) 

So, water (in terms of the word) is added to help split and breakdown macromolecules. 

I hope this helps!
~kaikers
aleksandrvk [35]3 years ago
3 0

Answer:

Water

Explanation:

Hydrolysis is the breaking of a molecule by the action of water. The water molecule releases H + and OH- ions into the solution and when a molecule is broken down hydrogen from the water molecule is transferred to one of the fragments of that molecule and the hydroxyl to another, thereby forming new compounds.  Therefore, we can conclude that during hydrolysis, the presence of water is required to decompose food macromolecules.

This action of water does not happen alone, it requires high pressure and temperature. In addition to accelerating the hydrolysis, an accelerating agent should be used, the most important being acids, enzymes and alkalis.

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Answer:

Only Fe^{3+}+Mg gives spontaneous reaction.

Explanation:

A redox reaction will be spontaneous if standard reduction potential (E^{0}) of the reaction is positive. Because it leads to negative standard gibbs free energy change (\Delta G^{0}), which is a thermodynamic condition for spontaneity of a reaction.

E^{0}=E^{0}(reduction)-E^{0}(oxidation)

Where E^{0}(reduction) and E^{0}(oxidation) represents standard reduction potential of reduction half cell and standard reduction potential of oxidation half cell.

(1) Oxidation:         Mg-2e^{-}\rightarrow Mg^{2+} ;  E_{Mg^{2+}\mid Mg}^{0}=-2.38V

Reduction:         Fe^{3+}+3e^{-}\rightarrow Fe ; E_{Fe^{3+}\mid Fe}^{0}=-0.04V

So, E^{0}=E_{Fe^{3+}\mid Fe}^{0}-E_{Mg^{2+}\mid Mg}^{0}=(-0.04+2.38)V=2.34V

Hence this pair will give spontaneous reaction.

(2) Similarly as above, E^{0}=E_{Pb^{2+}\mid Pb}^{0}-E_{Au^{+}\mid Au}^{0}=(-0.13-1.69)V=-1.82 V

Hence this pair will give non-spontaneous reaction.

(3) Similarly as above, E^{0}=E_{Ag^{+}\mid Ag}^{0}-E_{Br_{2}\mid Br^{-}}^{0}=(0.80-1.07)V=-0.27 V

Hence this pair will give non-spontaneous reaction.

(4)  Similarly as above, E^{0}=E_{Li^{+}\mid Li}^{0}-E_{Cr^{3+}\mid Cr}^{0}=(-3.04+0.74)V=-2.30 V

Hence this pair will give non-spontaneous reaction.

6 0
3 years ago
Write the symbol for every chemical element that has atomic number greater than 3 and atomic mass less than 15.4 u.
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44. Convert the following. Express your answers in
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Answer:

A =  0.75 ×10² KJ.

B = 3.9 ×10³ dg

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Explanation:

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7.5 ×10⁴ / 1000 = 0.75 ×10² KJ.

Joule is the smaller unit while kilo joule is the larger unit. One kilo joule equals to the thousand joule that's why we will divide the given value by 1000 in order to convert into KJ.

B = 3.9 ×10⁵ mg to decigrams.

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Decigram is larger unit while milligram is smaller unit. One decigram is equal to the 100 milligram. In order to convert the given value into  decigram we have to divide the value by 100.

C = 2.21 ×10⁻⁴ dL to micorliters

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Answer:

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Step 2: Make an ICE chart

We can relate the solubility product constant (Ksp) with the solubility (S) through an ICE chart.

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I                                0                    0

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E                                S                  2S

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