1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
guapka [62]
4 years ago
6

I need help with one and two. Polt them on the graph

Mathematics
1 answer:
sergejj [24]4 years ago
3 0
For the first one number it -9 all the way to positive 2 and put a dot on the negative 9. 9 is bigger than x so you draw a arrow going to the right. Same thing with number 2.
You might be interested in
Help me answer image sent. (I zoomed the graph so you can see it better.)
MAXImum [283]

Answer:

1. K

2. F

3. B

4. E

5. H

6. J

7 0
3 years ago
Read 2 more answers
2. 5 is 25% of what number?
ss7ja [257]

Answer:

10

Step-by-step explanation:

25% is 25 over 100 = 1 over 4 of a number (% means "out of 100")

Setting the number as x means x * 1 over 4 = 2.5

To find  x  we will divide both sides by 1 over 4, which is also multiplying by 4

2.5 * 4 = 10

6 0
4 years ago
I have 2 apples and my friend has 4 apples. if we add them together, what is the total?
Artyom0805 [142]

Answer: 6 apples

Step-by-step explanation: 4 + 2 = 6

4 0
3 years ago
Read 2 more answers
Find the missing side length of the right triangle. show work.
motikmotik

Answer:

6.32

Step-by-step explanation:

To find the side length on a right angled triangle we follow The Pythagorean Theorem:

{a}^{2}  +  {b}^{2}  =  {c}^{2}

c being the hypothesis (longest side: the hypotenuse is always opposite the right angle)

so..

{6}^{2}  +   {2}^{2}  =  {x}^{2}  \\ 36 + 4 =  {x}^{2}  \\ 40 =  {x}^{2} \\  \sqrt{40}   =  \sqrt{ {x}^{2} } \\

6.32 = x

8 0
2 years ago
Read 2 more answers
Let l(x) be the statement "x has an Internet connection" and C(x, y) be the statement "x and y have chatted over the Internet,"
Bas_tet [7]

The question is:

Let l(x) be the statement "x has an Internet connection" and C(x, y) be the statement "x and y have chatted over the Internet," where the domain for the variables x and y consists of all students in your class. Use quantifiers to express each of these statements.

a. Jerry does not have an Internet connection.

b. Rachel has not chatted over the Internet with Chelsea.

c. Jan and Sharon have never chatted over the Internet.

d. No one in the class has chatted with Bob.

e. Sanjay has chatted with everyone except Joseph.

f. Someone in your class does not have an Internet connection.

g. Not everyone in your class has an Internet connection.

h. Exactly one student in your class has an internet connection.

i. Everyone except one student in your class has an Internet connection.

j. Everyone in your class with an Internet connection has chatted over the Internet with at least one other student in your class.

k. Someone in your class has an Internet connection but has not chatted with anyone else in your class.

l. There are two students in your class who have not chatted with each other over the Internet.

m. There is a student in your class who has chatted with everyone in your class over the Internet.

n. There are at least two students in your class who have not chatted with the same person in your class.

o. There are two students in the class who between them have chatted with everyone else in the class.

Step-by-step explanation:

Note that: Because the arguments are variables, we write

Ix = I(x)

Cxy = C(x,y)

a. Jerry does not have an Internet connection.

~I(Jerry).

b. Rachel has not chatted over the internet with Chelsea.

~C(Rachel,Chelsea).

c. Jan and Sharon have never chatted over the internet.

~C(Jan,Sharon).

d. No one in the class has chatted with Bob.

~∃x C(x, Bob).

e. Sanjay has chatted with everyone except Joseph.

∀y (y ≠ Joseph → C(Sanjay, y)).

f. Someone in your class does not have an internet connection.

∃x ~Ix.

g. Not everyone in your class has an internet connection.

~∀x Ix.

h. Exactly one student in your class has an internet connection.

∃x (Ix ∧ ∀y (Iy → y = x)).

i. Everyone except one student in your class has an internet connection. This means exactly one student does not have a connection.

∃x (~Ix∧ ∀y (Iy → y = x)).

j. Everyone in your class with an internet connection has chatted over the internet with at least one other student in your class.

∀x (Ix → ∃y (Cxy ∧ x ≠ y)).

Assuming nobody can chat with him or herself, then

∀x (Ix → ∃y (Cxy))

k. Someone in your class has an internet connection but has not chatted with anyone else in your class.

∃x (Ix ∧ ∀y ~Cxy).

l. There are two students in your class who have not chatted with each other over the internet.

∃x ∃y (x ≠ y∧~Cxy).

m. There is a student in your class who has chatted with everyone in your class over the internet.

∃x ∀y Cxy.

n. There are at least two students in your class who have not chatted with the same person in your class. ∃x ∃y (x ≠ y ∧ ∃z (~Cxz ∧ ~Cyz)).

o. There are two students in the class who between them have chatted with everyone else in the class.

∃x ∃y (x ≠ y ∧ ∀z (Cxz ∨ Cyz)).

5 0
4 years ago
Other questions:
  • You have 800 square feet of the room reserved for tables
    6·1 answer
  • What is the first quartile<br> value of 16 18 20 14 17 27 33 9 + 12​
    11·1 answer
  • To a has 17 marbles the types are are aggies comets and cats eye she has twice as many aggies as comets she has one more cats ey
    10·1 answer
  • What is the slope intercept form of 3x+4y=-24
    15·2 answers
  • Solve for w<br> 1/2 (3w + 8) =25
    8·1 answer
  • How do you add and subtract intergers.
    15·2 answers
  • Simplify: 12.5 – 2.2 – 1.5 + 2.6
    14·1 answer
  • Find value of x. <br> using geometry
    15·2 answers
  • 69. The height of a triangle is 1 in more than the base. If the height is increased by 2 in while the base remains
    12·1 answer
  • Joelle spent 1 1/2 hours studying for her science test. Rileigh studied for 3/4 of Joelle’s time. What fraction of an hour did R
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!