B, it’s the point that the lines cross
Hi!
We can find the result by subtracting the minimum value from the maximum value, that's the value of the difference in the temperature for the day, and it is calculated like this:
10 - (-17) = 10 + 17 = 27
Hope this helps!
Answer:
angle B: 39
AC: 7.288
AB: 11.58
(note: you cut off the part about rounding so make sure that it's rounded correctly before you put in your answer)
Step-by-step explanation:
To solve this we will use SOH, CAH, TOA
we have the angle and the one opposite to it which means we can use either SOH or TOA
let's use TOA
tan(51)=(9/x)
x= 7.288
We can now use pahtagaryous theroem to solve for the hyptonouse
we have
9²+7.288²=C²
C=11.58
Finally, to find angle B we will recall that the angles of a triangle must add to 180.
51+90+a=180
a=39
1) 20x+5y=120
Stp1: 5y=120-20x
Stp2: 5y=(120/5 and -20x/5)= [y=24-4x]
finding x:
20x+5(24-4x)=120
Stp1: 5*24=120,-4x*5=-20
20x+120-20x=120
Stp2: subtract 120 on both sides of = sign
20x-20x=0
Stp3: subtract the variables:
[x=0]
finding y:
20(0)+5y=120
stp1: multiply 20*0
5y=120
stp2: divide 120 by 5
[y=24]
2) 10x+7.5y=80
Stp1: move 7.5y to other sign of =
10x=80-7.5y
Stp2: divide by 10
[x=8-.75y]
substitute x and re do original:
stp1: 10(8-.75y)+7.5y=80
stp2: 80-7.5y+7.5y=80
stp3: subtract variabled num. with variabled num. and whole num. with whole number: [y=0]
solve for x:
10x-7.5(0)=80
10x=80
[x=8]
check:
10(8)+7.5(0)=80
80+0=80
[80=80]
It equals 22.............