Translate it 8units to the right then reflect it over the line y=-3
Why?
- We can see the Quadrilateral is in Quadrant 3.
- If we translate it by 8units right it come to Quadrant 4.
- Now reflect it over line y=-3
- we will get Quadrilateral 2
Answer:
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Step-by-step explanation:
Answer:
f(x) = –x2
Step-by-step explanation:
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Answer:
![x\approx 24.0,\\y\approx 46.4](https://tex.z-dn.net/?f=x%5Capprox%2024.0%2C%5C%5Cy%5Capprox%2046.4)
Step-by-step explanation:
Let the height of the largest triangle marked be
. We can set up the following equation:
(if you're unfamiliar with trig, this is likely introduced to you as 30-60-90 triangle rules)
This height is also a leg of a 45-45-90 triangle, as marked in the diagram. From the isosceles-base-theorem, the other leg of this triangle must also be equal to
. Therefore, we can use the Pythagorean theorem to solve for
:
(you can also use trig or 45-45-90 triangle rules which are derived from the Pythagorean theorem)
Segment
consists of two shorter segments, a left segment and a right segment. We've already found that the left segment is equal to 17. To find the right segment we can use trig, the Pythagorean theorem, or 30-60-90 triangle rules (derived from the Pythagorean theorem):
Using Pythagorean Theorem:
![y_{right}=\sqrt{34^2-17^2}\approx \boxed{29.4}](https://tex.z-dn.net/?f=y_%7Bright%7D%3D%5Csqrt%7B34%5E2-17%5E2%7D%5Capprox%20%5Cboxed%7B29.4%7D)
Therefore, we have:
![y=17+29.4=\boxed{46.4}](https://tex.z-dn.net/?f=y%3D17%2B29.4%3D%5Cboxed%7B46.4%7D)