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schepotkina [342]
3 years ago
8

Parking at a large university has become a very big problem. University administrators are interested in determining the average

parking time​ (e.g. the time it takes a student to find a parking​ spot) of its students. An administrator inconspicuously followed 260 students and carefully recorded their parking times. Identify the population of interest to the university administration.
Mathematics
1 answer:
Oduvanchick [21]3 years ago
7 0

Answer:

The 260 students that are followed.

Step-by-step explanation:

According to the situation explained in the question, the university administration is trying to collect data on the students' parking times to figure out a solution for the parking problem in the university.

After following and collecting data from 260 students, the population of interest to the university administration should be the all 260 students that the data is collected from because population of interest describes a "population" that are being studied and having data collected from them.

I hope this answer helps.

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Answer:

$3.51

Step-by-step explanation:

We change 5.4% into a decimal which is .054, we then multiply 65 by .054

$65  x  .054 = $3.51

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You can work at most 20 hours next week. You need to earn at least $92 to cover your weekly expenses. Your dog-
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A cylinder has radius r and height h. A. How many times greater is the surface area of a cylinder when both dimensions are multi
Ierofanga [76]

Answer: A. Factor 2 => 4x greater

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                   Factor 5 => 25x greater

Step-by-step explanation: A. A cylinder is formed by 2 circles and a rectangle in the middle. That's why surface area is given by circumference of a circle, which is the length of the rectangle times height of the rectangle, i.e.:

A = 2.π.r.h

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A_{2} = 2.π.2r.2h

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\frac{A_{2}}{A_{1}} = \frac{8.\pi.rh}{2.\pi.rh} = 4

Doubling radius and height creates a surface area of a cylinder 4 times greater.

<u>By factor 3:</u>

A_{3} = 2.\pi.3r.3h

A_{3} = 18.\pi.r.h

Comparing areas:

\frac{A_{3}}{A_{1}} = \frac{18.\pi.r.h}{2.\pi.r.h} = 9

Multiplying by 3, gives an area 9 times bigger.

<u>By factor 5</u>:

A_{5} = 2.\pi.5r.5h

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Comparing:

\frac{A_{5}}{A_{1}} = \frac{50.\pi.r.h}{2.\pi.r.h} = 25

The new area is 25 times greater.

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