Hello!
This question is an example of function notation. Function notation is basically f(x) , said as "f of x". To solve this problem, you need to substitute x = 2 into each x-value in this equation. F(2) is written as function notation, while x = 2 is not.
F(2) = 4x² - 3x + 5
F(2) = 4(2)² - 3(2) + 5
F(2) = 4(4) - 6 + 5
F(2) = 16 - 6 + 5
F(2) = 15
Therefore, the value of F(2) is 15.
I think it’s A i’m not 100% sure tho ❤️
The answer is the one on the top
Answer:
x = 30 and y = -34
Step-by-step explanation:
Given the following functions
(1/4)^(x+y) = 256... 1
log₄(x-y) = 3.... 2
From equation 2;
x-y = 4³
x-y = 64
x = 64 + y ... 3
Substitutw 3 into 1
From 1:
(1/4)^(x+y) = 256
(1/4)^(64+y+y) = 256
(1/4)^(64+2y) = 256
Take log₄ of both sides
64+2y log₄ (1/4) = log₄256
-(64+2y) = 4log₄4
-(64+2y) = 4
64+2y = -4
2y = -4 - 64
2y = -68
y = -34
Since
x = 64 + y .
x = 64 - 34
x = 30
Hence x = 30 and y = -34
