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3 years ago

HELP PLEASE FAST!!!!!

Mathematics

1 answer:

MArishka [77]3 years ago

5 0

Answer:

$10.50 an hour

Step-by-step explanation:

210/20 = 10.5

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Part A: The sum of the measures of UWZ is 90, so UWV and UWZ are_________ angles.

kiruha [24]

Answer: A. UWV and UWZ are complementary angles.

B.They do not overlap, so UWV and VWX are supplementary angles

Step-by-step explanation:

Complementary angles add up to 90.

Supplementary angles do not overlap.

4 0

3 years ago

For positive test result, the number of those who did not lie and lie are 11 and 41, respectively. Those of the negative test re

vagabundo [1.1K]

P(subject lied | negative results) = 4/19

P(negative results | subject lied) = 8/49

I am hoping that these answers have satisfied your queries and it will be able to help you in your endeavors, and if you would like, feel free to ask another question.

3 0

3 years ago

Three times a number increased by four is<br> less than -62.

klemol [59]

Answer: x<-22

Step-by-step explanation:

3x+4<-62

3x<-66

x<-22

6 0

3 years ago

Read 2 more answers

The sales of new cars at a dealership increased by 7% this year to 382. Find the number of sales the previous year. Round your a

ladessa [460]

If "x" is the number of car sales last year, then (x + 0.07x) is this years sales.
x + 0.07x = 382
1.07x = 382
x = 382/1.07
x = 357

7 0

3 years ago

You would like to know whether forwards in a basketball league average the same (or different) numbers of points than the overal

Akimi4 [234]

Answer:

The critical t-value for such a test given an alpha level of 0.05 is 2.26

Step-by-step explanation:

Null hypothesis : $H_0:\mu = 7.5$

Alternate hypothesis : $H_a:\mu \neq 7.5$

Population mean = $\mu = 7.5$

Data : 10, 9, 6, 11, 13, 14, 9, 9, 9, and 10

Mean = $\bar{x}=\frac{\text{Sum of all observations}}{\text{no. of observations}}$

Mean = $\frac{10+9+6+11+13+14+9+9+ 9+ 10}{10}$

Mean =10

Standard deviation : $\sqrt{\frac{\sum(x-\bar{x})^2}{n}}$

Standard deviation : $\sqrt{\frac{(10-10)^2+(9-10)^2+(6-10)^2+(11-10)^2+(13-10)^2+(14-10)^2+(9-10)^2+(9-10)^2+(9-10)^2+(10-10)^2}{10}}$

Standard deviation s :2.144

$t = \frac{x-\mu}{\frac{s}{\sqrt{n}}}t = \frac{10-7.5}{\frac{2.144}{\sqrt{10}}}t=3.687$

Df = n-1 = 10-1 = 9

T critical = $t_{(df,\alpha)}=t_(9,0.05)=2.26$

T calculated > T critical

So, We failed to accept null hypothesis

Hence the critical t-value for such a test given an alpha level of 0.05 is 2.26

5 0

3 years ago