Answer:
g(4x) = 192x^3
Step-by-step explanation:
For this problem, f(x) is irrelevant since we are simply are dealing with g(x). We will simply replace the value of x in g(x) with 4x. So let's do that.
g(x) = 3x^3
g(4x) = 3(4x)^3
g(4x) = 3(4^3)(x^3)
g(4x) = 3(64)(x^3)
g(4x) = 192x^3
Hence, g(4x) is 192x^3.
Cheers.
Answer:
6(2x-3)= -9 given
12x-18= -9 distribute
12x-18+18= -9+18 addition
12x= 9 division
x= 3/4 solution
Step-by-step explanation:
Answer: 1.4 seconds
<u>Step-by-step explanation:</u>
The equation is: h(t) = at² + v₀t + h₀ where
- a is the acceleration (in this case it is gravity)
- v₀ is the initial velocity
- h₀ is the initial height
Given:
- a = -9.81 (if it wasn't given in your textbook, you can look it up)
- v₀ = 12
- h₀ = 3
Since we are trying to find out when it lands on the ground, h(t) = 0
EQUATION: 0 = 9.81t² + 12t + 3
Use the quadratic equation to find the x-intercepts
a=-9.81, b=12, c=3

Note: Negative time (-0.2) is not valid
Answer:
84
Step-by-step explanation:
The interquartile range is obtained using the relation :
Third quartile (Q3). - First quartile (Q1)
From. The boxplot :
Q3 = 96
Q1 = 12
Interquartile range (IQR) = Q3 - Q1 = 96 - 12 = 84
Answer:
a) <em>Slope of the line m = ∞</em>
<em>b) Slope of the line m =0</em>
Step-by-step explanation:
<u><em>Explanation:-</em></u>
<u><em>Step(i):-</em></u>
<em>Given points are ( 7,7) and (7,-8)</em>
<em>Slope of the line</em>
<em> </em>
<em />
<em> </em>
<em />
<em> m = ∞</em>
<u><em>Step(ii):-</em></u>
Given points are (-6,7) and (9,7)
<em>Slope of the line</em>
<em> </em>
<em />
<em> </em>
<em />
<em>Slope of the line m =0</em>