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Lana71 [14]
3 years ago
13

The phone company A Fee and Fee has a monthly cellular plan where a customer pays a flat monthly fee and then a certain amount o

f money per minute used on the phone. If a customer uses 110 minutes, the monthly cost will be $59. If the customer uses 600 minutes, the monthly cost will be $157. A) Find an equation in the form y
Mathematics
1 answer:
11111nata11111 [884]3 years ago
6 0

Answer:

y = 0.2x + 37

Step-by-step explanation:

A) Find an equation in the form y = mx + b, where x is the number of monthly minutes used and y is the total monthly of the Ringular plan.

(x, y) = (minutes, cost)

(110, 59)

(600, 157)

slope = m = dy/dx

dy/dx = change in y/change in x

m = dy/dx

m = (157 - 59)/(600-110)

m = 98/490

m = 0.2

a) the linear equation:

y - 59 = 0.2(x - 110)

y - 59 = 0.2x - 22

y = 0.2x - 22 + 59

y = 0.2x + 37

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Q3) f(x) 2x^2 - 5x, g(x) = 3x^3 find g(4x)
mrs_skeptik [129]

Answer:

g(4x) = 192x^3

Step-by-step explanation:

For this problem, f(x) is irrelevant since we are simply are dealing with g(x).  We will simply replace the value of x in g(x) with 4x.  So let's do that.

g(x) = 3x^3

g(4x) = 3(4x)^3

g(4x) = 3(4^3)(x^3)

g(4x) = 3(64)(x^3)

g(4x) = 192x^3

Hence, g(4x) is 192x^3.

Cheers.

4 0
3 years ago
Please*** I need help with this basic algebra problem.<br> FILL IN THE MISSING STEPS.
Oduvanchick [21]

Answer:

6(2x-3)= -9               given

12x-18= -9                distribute

12x-18+18= -9+18      addition

12x= 9                       division

x= 3/4                        solution

Step-by-step explanation:

5 0
3 years ago
A ball is thrown in the air from a height of 3 m with an initial velocity of 12 m/s. To the nearest tenth of a second, how long
stepladder [879]

Answer:  1.4 seconds

<u>Step-by-step explanation:</u>

The equation is: h(t) = at² + v₀t + h₀          where

  • a is the acceleration (in this case it is gravity)
  • v₀ is the initial velocity
  • h₀ is the initial height

Given:  

  • a = -9.81 (if it wasn't given in your textbook, you can look it up)
  • v₀ = 12
  • h₀ = 3

Since we are trying to find out when it lands on the ground, h(t) = 0

EQUATION:   0 = 9.81t² + 12t + 3

Use the quadratic equation to find the x-intercepts

                        a=-9.81, b=12, c=3

x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}\\\\\\x=\dfrac{-(12)\pm \sqrt{(12)^2-4(-9.81)(3)}}{2(-9.81)}\\\\\\x=\dfrac{-12\pm 16.2}{-19.62}\\\\\\x=\dfrac{-12+ 16.2}{-19.62}=-0.2\qquad x=\dfrac{-12- 16.2}{-19.62}=\large\boxed{1.4}\\

Note: Negative time (-0.2) is not valid

4 0
3 years ago
I could use some help!!
12345 [234]

Answer:

84

Step-by-step explanation:

The interquartile range is obtained using the relation :

Third quartile (Q3). - First quartile (Q1)

From. The boxplot :

Q3 = 96

Q1 = 12

Interquartile range (IQR) = Q3 - Q1 = 96 - 12 = 84

6 0
2 years ago
Fill in the blanks below.
Dmitry_Shevchenko [17]

Answer:

a) <em>Slope of the line m = ∞</em>

<em>b) Slope of the line  m =0</em>

Step-by-step explanation:

<u><em>Explanation:-</em></u>

<u><em>Step(i):-</em></u>

<em>Given points are ( 7,7) and (7,-8)</em>

<em>Slope of the line</em>

<em>                      </em>m = \frac{y_{2} - y_{1} }{x_{2}-x_{1}  }<em />

<em>                     </em>m = \frac{-8-7 }{7-7  } = \frac{-15}{0} = infinite<em />

<em>                   m = ∞</em>

<u><em>Step(ii):-</em></u>

Given points are (-6,7) and (9,7)

<em>Slope of the line</em>

<em>                      </em>m = \frac{y_{2} - y_{1} }{x_{2}-x_{1}  }<em />

<em>                     </em>m = \frac{7-7  }{9-(-6)  } = \frac{0}{15} = 0<em />

<em>Slope of the line  m =0</em>

6 0
3 years ago
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