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Lana71 [14]
3 years ago
13

The phone company A Fee and Fee has a monthly cellular plan where a customer pays a flat monthly fee and then a certain amount o

f money per minute used on the phone. If a customer uses 110 minutes, the monthly cost will be $59. If the customer uses 600 minutes, the monthly cost will be $157. A) Find an equation in the form y
Mathematics
1 answer:
11111nata11111 [884]3 years ago
6 0

Answer:

y = 0.2x + 37

Step-by-step explanation:

A) Find an equation in the form y = mx + b, where x is the number of monthly minutes used and y is the total monthly of the Ringular plan.

(x, y) = (minutes, cost)

(110, 59)

(600, 157)

slope = m = dy/dx

dy/dx = change in y/change in x

m = dy/dx

m = (157 - 59)/(600-110)

m = 98/490

m = 0.2

a) the linear equation:

y - 59 = 0.2(x - 110)

y - 59 = 0.2x - 22

y = 0.2x - 22 + 59

y = 0.2x + 37

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Find the area of the region enclosed by f(x) and the x axis for the given function over the specified u reevaluate f(x)=x^2+3x+4
lord [1]

Answer:

A = 68 unit^2

Step-by-step explanation:

Given:-

The piece-wise function f(x) is defined over an interval as follows:

                       f(x) =  { x^2+3x+4    , x < 3

                       f(x) =  { x^2+3x+4     , x≥3

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Find the area of the region enclosed by f(x) and the x axis

Solution:-

- The best way to tackle problems relating to piece-wise functions is to solve for each part individually and then combine the results.

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                       f(x) = x^2+3x+4

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                      A1 = \int\limits^a_b {f(x)} \, dx

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                     A1 = \int\limits^a_b {x^2+3x+4} \, dx\\\\A1 = \frac{x^3}{3} + \frac{3x^2}{2} + 4x |\limits_-_3^3 \\\\A1 = \frac{3^3}{3} + \frac{3*3^2}{2} + 4*3 - \frac{-3^3}{3} - \frac{3(-3)^2}{2} - 4(-3)\\\\A1 = 9 + 13.5 +12 + 9-13.5+12\\\\A1 =42 unit^2

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                      A2 = \int\limits^a_b {f(x)} \, dx

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                     A2 = \int\limits^a_b {4x+10} \, dx\\\\A2 = 2x^2 + 10x |\limits_3^4 \\\\A2 = 2*(4)^2 + 10*4 - 2*(3)^2 - 10*3\\\\A2 = 32 + 40 - 18-30\\\\A2 =26 unit^2

- The total area "A" bounded by the piece-wise function over the entire domain [ -3 , 4 ] is given:

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