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Lana71 [14]
2 years ago
13

The phone company A Fee and Fee has a monthly cellular plan where a customer pays a flat monthly fee and then a certain amount o

f money per minute used on the phone. If a customer uses 110 minutes, the monthly cost will be $59. If the customer uses 600 minutes, the monthly cost will be $157. A) Find an equation in the form y
Mathematics
1 answer:
11111nata11111 [884]2 years ago
6 0

Answer:

y = 0.2x + 37

Step-by-step explanation:

A) Find an equation in the form y = mx + b, where x is the number of monthly minutes used and y is the total monthly of the Ringular plan.

(x, y) = (minutes, cost)

(110, 59)

(600, 157)

slope = m = dy/dx

dy/dx = change in y/change in x

m = dy/dx

m = (157 - 59)/(600-110)

m = 98/490

m = 0.2

a) the linear equation:

y - 59 = 0.2(x - 110)

y - 59 = 0.2x - 22

y = 0.2x - 22 + 59

y = 0.2x + 37

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Please answer this correctly
natka813 [3]

Answer: Rectangular pyramid

Step-by-step explanation:

When you think about it, a pyramid has 3 faces that are triangular!

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8 0
2 years ago
Help!!! Huge milestone!! I will give crown!!! The value of y is directly proportional to the value of x. If y=8 when x=10, what
PolarNik [594]

Answer:30

Step-by-step explanation:the initial statement is

y ∝ x

to convert to an equation multiply by k the constant

of variation

⇒ y = k x

to find k use the given condition

y = − 24 when x = 8 y = k x ⇒ k = y x = −22

∣

∣

∣22 y = − 3 x 22

∣∣∣

−−−−−−−−−−−−−−

when  x = 10

then y = − 3 × 10 = −30

6 0
3 years ago
HELP ASAP!!!
gizmo_the_mogwai [7]

Answer:

The answers to this question are 1,2,4,6. Hope this helps you

Step-by-step explanation:

8 0
2 years ago
40% of the tickets sold at a school carnival were early-admission tickets. If the school sold 65 tickets in all, how many early-
kupik [55]

Answer:

39

Step-by-step explanation:

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2 years ago
Read 2 more answers
Consider two markets: the market for cat food and the market for dog food. The initial equilibrium for both markets is the same,
umka21 [38]

Answer:

elasticity supply of dog food = 2.61

elasticity supply of cat food = 1.71

Step-by-step explanation:

The midpoint formula for elasticity is:

Elasticity = \frac{(Q2-Q1)/[(Q2+Q1)/2]}{(P2-P1)/[(P2+P1)/2]}

Point 1: Q = 39.0 and P = 5.50

Point 2: Q = 101.0 and P = 7.75

Elasticity\ supply\ of\ dog\ food = \frac{(101.0-39.0)/[101.0+39.0)/2]}{(7.75-5.50)/[(7.75+5.50)/2]}=2.61

Doing the same for the cat food:

Elasticity\ supply\ of\ cat\ food = \frac{(71.0-39.0)/[71.0+39.0)/2]}{(7.75-5.50)/[(7.75+5.50)/2]}=1.71

4 0
3 years ago
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