Answer:
y = -3x + 7
Step-by-step explanation:
Choosing two points from the given table:
Let (x1, y1) = (-3, 16)
(x2, y2) = (-1, 10)
Plug these given values into the slope formula:
m = (y2 - y1)/(x2 - x1)
= (10 - 16) / (-1 - (-3))
= -6 / (-1 + 3)
= -6/2
= -3
Therefore, the slope is -3.
Next, choose one of the points and plug into the <u>point-slope form</u>:
Let's use (-1, 10) as (x1, y1):
y - y1 = m(x - x1)
y - 10 = -3(x - (-1))
y - 10 = -3(x + 1)
y - 10 = -3x - 3
Add 10 on both sides to isolate y:
y - 10 + 10 = -3x - 3 + 10
y = -3x + 7
Y=mx+c isn't an equation to solve. It's the slope-intercept formula for graphing lines.
y and x are the variables, and m and c are the constants.
As an example, the line y=4x+2 looks like this:
Millimeter centimeter meter kilometer
Answer:
Present value = $4,122.4
Accumulated amount = $4,742
Step-by-step explanation:
Data provided in the question:
Amount at the Start of money flow = $1,000
Increase in amount is exponentially at the rate of 5% per year
Time = 4 years
Interest rate = 3.5% compounded continuously
Now,
Accumulated Value of the money flow = 
The present value of the money flow = 
= 
= ![1000\left [\frac{e^{0.015t}}{0.015} \right ]_0^4](https://tex.z-dn.net/?f=1000%5Cleft%20%5B%5Cfrac%7Be%5E%7B0.015t%7D%7D%7B0.015%7D%20%5Cright%20%5D_0%5E4)
= ![1000\times\left [\frac{e^{0.015(4)}}{0.015} -\frac{e^{0.015(0)}}{0.015} \right]](https://tex.z-dn.net/?f=1000%5Ctimes%5Cleft%20%5B%5Cfrac%7Be%5E%7B0.015%284%29%7D%7D%7B0.015%7D%20-%5Cfrac%7Be%5E%7B0.015%280%29%7D%7D%7B0.015%7D%20%5Cright%5D)
= 1000 × [70.7891 - 66.6667]
= $4,122.4
Accumulated interest = 
= 
= $4,742