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goldenfox [79]
3 years ago
9

Seiji and Gavin both worked hard over the summer. Together, they earned a total of $425. Gavin earned $25 more than Seiji. How m

uch did each of them earn?
Mathematics
1 answer:
schepotkina [342]3 years ago
5 0
S + g = 425
g = s + 25
-----------------
We will use the method of substitution:
s + s + 25 = 425
2 s = 425 - 25
2 s = 400
s = 400 : 2
s = $425
g = 200 + 25
g = $225
Answer: Seiji earned $200 and Gavin earned $225.
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The scores of fourth grade students on a mathematics achievement test follow a normal distribution with a mean of 75 and standar
mamaluj [8]

Answer:

The appropriate solution is:

(a) 0.1056

(b) 0

(c) 0.9544

Step-by-step explanation:

The given values are:

Mean,

\mu = 75

Standard deviation,

\sigma = 4

(a)

⇒  P(x>80)=1-(x

                     =1-P[\frac{x-\mu}{\sigma}

                     =1-P[\frac{x-\mu}{\sigma}

                     =1-P(z

By using the table, we get

                     =1-0.8944

                     =0.1056

(b)

According to the question, the values are:

n = 64

\mu_\bar{x} = 75

Now,

⇒  \sigma_\bar{x} = \frac{\sigma}{\sqrt{n} }

         = \frac{4}{\sqrt{64} }

         = \frac{4}{8}

         = 0.5

⇒  P(\bar {x} >80 ) = 1 - P(\bar x

                      =1 - P[\frac{(\bar x-\mu_\bar x)}{\sigma \bar x} < \frac{80-75}{0.5}  ]

                      =1-P(z

By using the table, we get

                      =1-1

                      =0

(c)

As we know,

⇒ \sigma_\bar x = \frac{\sigma}{\sqrt{n} }

        = \frac{4}{\sqrt{64} }

        = \frac{4}{8}

        = 0.5

then,

= P(74< \bar x

= P[\frac{74-75}{0.5} < \frac{\bar x-\mu \bar x}{\sigma \bar x} < \frac{76-75}{0.5} ]

= P(-2

= P(z

By using the table, we get

= 0.9772-0.0228

= 0.9544

7 0
3 years ago
6: Abby is making a decoration. When folded, the decoration is a triangular pyramid made of four congruent equilateral triangles
NeTakaya

Answer:

85 square inches  

Step-by-step explanation:

I think your question missed key information, allow me to add in and hope it will fit the orginal one. Please have a look at the attached photo

My answer:

From the question, four congruent equilateral triangles with the following information:

  • The height: 6.06 inches
  • The base : 7 inches

=> The area of the quilateral triangle is:

=1/2*the base*the height

= 1/2*60.6*7

= 21.21 square inches

=> the surface area of Abby's decoration is:

= 4 * The area of the quilateral triangle

= 4*21.21

= 84.84 square inches  

≈ 85 square inches  

Hope it will find you well.

7 0
4 years ago
Find the area of the figure <br> area: cm2
nasty-shy [4]

Answer:

132cm ^ 2

Step-by-step explanation:

First solve the top rectangle, 4x7 = 28cm

then solve the bottom rectangle, 8x7 = 56cm

then solve the triangle, we know the entire bottom is 19cm, and 7 is subtracted, thereforth leavin 12, since there is 2 triangles its a base of 6, with a height of 8 making 48cm (and since there is 2 triangles no need to divide by 2)

28+56+48 = 132cm^2

-- Gage Millar, Algebra 2 Tutor

7 0
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It costs $6.45 to buy 5 songs on I-tunes. How much does it cost to buy 20 songs?
babunello [35]

Answer:$25.80

Step-by-step explanation:

6.45/5 = 1.29

1.29 x 20 =25.80

5 0
2 years ago
I need help with 1 2 3
g100num [7]
D D B I think this should be right
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