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goldenfox [79]
3 years ago
9

Seiji and Gavin both worked hard over the summer. Together, they earned a total of $425. Gavin earned $25 more than Seiji. How m

uch did each of them earn?
Mathematics
1 answer:
schepotkina [342]3 years ago
5 0
S + g = 425
g = s + 25
-----------------
We will use the method of substitution:
s + s + 25 = 425
2 s = 425 - 25
2 s = 400
s = 400 : 2
s = $425
g = 200 + 25
g = $225
Answer: Seiji earned $200 and Gavin earned $225.
You might be interested in
If the price of 23 toys are $276, then what will be the price (Rs.) of 12 toys​
aliya0001 [1]

Answer:

Price of 23 toys = $276

Price of 1 toy =

276 \div 23 \\  = 12 \: dollars

Price of 12 toys =?

Price of 12 toys =

12 \times 12 \\  = 144 \: dollars

4 0
3 years ago
WILL MARK BRAINLIEST IF CORRECT❤️❤️<br> Simplify the expression -5+i/2i<br> Step by step
zhenek [66]

Answer:

For complex numbers,

a + bi and a - bi

they have the interesting property that if you add them you get the real number 2a

and if you multiply them , because of the difference of square pattern, you get a^2 - b^2 i^2

But since i^2 = -1, we end up with a real number as a product.

e.g. 6 - 5i and 6 + 5i are conjugates of each other

sum = 6-5i + 6+5i = 12

product = 36 - 25i^2

= 36 -(-25) = 61

Your question is even easier, since the denominator is a monomial instead of a binomial, so we just have to multiply by i/i

Also I believe, according to the answer, that you have a typo, and you meant

(-5+i)/(2i)

= (-5+i)/(2i) *i/i

= (-5i + i^2)/2i^2)

= (-5i +i^2)/-2

= (-5i - 1)/-2

= (1 + 5i)/2 or they way they have it: 1/2 + 5i/2

5 0
3 years ago
Read 2 more answers
Seventy percent of all vehicles examined at a certain emissions inspection station pass the inspection. Assuming that successive
NeX [460]

Answer:

(a) 0.343

(b) 0.657

(c) 0.189

(d) 0.216

(e) 0.353

Step-by-step explanation:

Let P(a vehicle passing the test) = p

                        p = \frac{70}{100} = 0.7  

Let P(a vehicle not passing the test) = q

                         q = 1 - p

                         q = 1 - 0.7 = 0.3

(a) P(all of the next three vehicles inspected pass) = P(ppp)

                           = 0.7 × 0.7 × 0.7

                           = 0.343

(b) P(at least one of the next three inspected fails) = P(qpp or qqp or pqp or pqq or ppq or qpq or qqq)

      = (0.3 × 0.7 × 0.7) + (0.3 × 0.3 × 0.7) + (0.7 × 0.3 × 0.7) + (0.7 × 0.3 × 0.3) + (0.7 × 0.7 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.3)

      = 0.147 + 0.063 + 0.147 + 0.063 + 0.147 + 0.063 + 0.027

      = 0.657

(c) P(exactly one of the next three inspected passes) = P(pqq or qpq or qqp)

                 =  (0.7 × 0.3 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.7)

                 = 0.063 + 0.063 + 0.063

                 = 0.189

(d) P(at most one of the next three vehicles inspected passes) = P(pqq or qpq or qqp or qqq)

                 =  (0.7 × 0.3 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.7) + (0.3 × 0.3 × 0.3)

                 = 0.063 + 0.063 + 0.063 + 0.027

                 = 0.216

(e) Given that at least one of the next 3 vehicles passes inspection, what is the probability that all 3 pass (a conditional probability)?

P(at least one of the next three vehicles inspected passes) = P(ppp or ppq or pqp or qpp or pqq or qpq or qqp)

=  (0.7 × 0.7 × 0.7) + (0.7 × 0.7 × 0.3) + (0.7 × 0.3 × 0.7) + (0.3 × 0.7 × 0.7) + (0.7 × 0.3 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.7)

= 0.343 + 0.147 + 0.147 + 0.147 + 0.063 + 0.063 + 0.063

                  = 0.973  

With the condition that at least one of the next 3 vehicles passes inspection, the probability that all 3 pass is,

                         = \frac{P(all\ of\ the\ next\ three\ vehicles\ inspected\ pass)}{P(at\ least\ one\ of\ the\ next\ three\ vehicles\ inspected\ passes)}

                         = \frac{0.343}{0.973}

                         = 0.353

3 0
4 years ago
Read 2 more answers
How do you break apart the factor 42 using place values
VLD [36.1K]

Let's break apart 42.

The 4 is in the tens. The 2 is in the ones.

                           Place Value starting from Thousands

                            Thousands  Hundreds  Tens  Ones

                            _________ ________ ____ _____

                                                                       4          2

So this is how we break up numbers using place value.

Hope this helps!

5 0
3 years ago
Evaluate the expression 5(8y+3r-5z) if r=3,y=5/8,and z=2
snow_lady [41]
First you plug in the missing values
5(8×5/8+3×3-5×2) = 20
3 0
3 years ago
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