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-BARSIC- [3]
3 years ago
10

: To receive gym credit without taking a gym class. J.T. must complete 75 hours of exercise throughout the semester. J.T. has al

ready completed 50 hours of exercise, and there are 4 weeks remaining in the semester. Assume J.T. plans to complete the same amount of exercise in each of the remaining weeks. ​Write an inequality to represent the scenario. Let h represent the number of hours J.T. has to exercise in each of the remaining weeks. How many hours will J.T. have to exercise each week to receive gym credit? Enter your inequality, answer, and work in the box provided.
Mathematics
1 answer:
VARVARA [1.3K]3 years ago
8 0

Answer:

H >= 6.25

6.5 hours per week

Step-by-step explanation:

75-50=25

JT must complete 25 more hours of exercise in 4 weeks.  25/4=6.25.  So JT has to exercise 6.5 hours each week.

>= (means greater than or equal to)

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Hello! Anyone able to help me with question 3 + explanation too? Thanks!
taurus [48]

Answer:

2 or 12

Step-by-step explanation:

The answer that we will use this equation 1/t1 +1/t2=1/ttotal

where t1 is the time of smaller pipe while t2 is the of the larger pipe

Given t total =4 while t2 is equal to t2=t1-6

So know you can solve the problem by changing it into (2t1-6)/(t1*(t1-6))=1/4

8( t1-3)=(t1^2-6t1)

t1^2-14t1+24=0

t1=2 or 12

5 0
4 years ago
Read 2 more answers
The coordinates of the vertices of a triangle are 2,3 5,1 and 6,4 after one reflection the coordinates of the vertices of the tr
VikaD [51]

Answer:

it is being reflected by the x axis

6 0
3 years ago
⊙O and ⊙P are given with centers (−2, 7) and (12, −1) and radii of lengths 5 and 12, respectively. Using similarity transformati
goldenfox [79]

Answer:

Whereby circle \bigodotP can be obtained from circle \bigodotO by applying the transformations of a translation of T₍₁₄, ₋₈₎ followed by a dilation by a scale factor of 2.4, \bigodotO is similar to \bigodotP

Step-by-step explanation:

The given center of the circle \bigodotO = (-2, 7)

The radius of \bigodotO, r₁ = 5

The given center of the circle \bigodotP = (12, -1)

The radius of \bigodotP, r₂ = 12

The similarity transformation to prove that \bigodotO and \bigodotP are similar are;

a) Move circle \bigodotO 14 units to the right and 8 units down to the point (12, -1)

b) Apply a scale of S.F. = r₂/r₁ = 12/5 = 2.4

Therefore, the radius of circle \bigodotO is increased by 2.4

We then obtain \bigodotO' with center at (12, -1) and radius r₃ = 2.4×5 = 12 which has the same center and radius as circle \bigodotP

∴ Circle \bigodotP can be obtained from circle \bigodotO by applying similarity transformation of translation of T₍₁₄, ₋₈₎ followed by a dilation by a scale factor of 2.4, \bigodotO is similar to \bigodotP.

7 0
3 years ago
Please help !!!!!!!!!
vodka [1.7K]

Answer:

A= 41°   a=9.84...  b=11.32...

Step-by-step explanation:

given B = 49° and C = 90°

and A + B + C = 180

so  49+90+A=180

A= 41°

we also know c (small)  is 15 units

and maybe you know this  SOH CAH TOA?   no, i'm not calling anyone names :P  this is just the mnemonic to memorize how sin , cos and tan fit sin(Ф)=Opp/Hyp   Cos(Ф)=Adj/Hyp  Tan(Ф)=Opp/Adj

Hyp is the hypontenuse of the triangle ( the long side). Opposite (Opp) means the side opposite from what ever angle you are starting at..adjacent (Adj) means what ever angle is next to where you are starting from.

use Cos(49) to find the side a

a is an adjacent side to the 49 angle.  We know the Cos and we know the Hyp .. so solve for adj...  

Cos(Ф)=Adj/ Hyp

Hyp*Cos(Ф)=Adj    

15*Cos(49)= Adj

9.84...=Adj=a

now lets' use sin for the opposite side or b

sin(Ф)=Opp/Hyp

Hyp*Sin(Ф) = Opp

15*sin(49)= Opp

11.32...= Opp =b

 

7 0
3 years ago
Can someone please help me ?
Alex

Answer:

  B.  π(3/2)²h

  (27/4)π cubic inches

Step-by-step explanation:

A. The formula for the volume of a cylinder is ...

  V = πr²h

The radius (r) is half the diameter, so for a diameter of 3 inches, the radius is 3/2 inches. When this is put into the formula, the volume is ...

  V = π(3/2)²h . . . . . . matches choice B

__

B. When h=3, the volume evaluates to ...

  V = π(9/4)(3) = (27/4)π . . . . cubic inches

8 0
3 years ago
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