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-BARSIC- [3]
3 years ago
10

: To receive gym credit without taking a gym class. J.T. must complete 75 hours of exercise throughout the semester. J.T. has al

ready completed 50 hours of exercise, and there are 4 weeks remaining in the semester. Assume J.T. plans to complete the same amount of exercise in each of the remaining weeks. ​Write an inequality to represent the scenario. Let h represent the number of hours J.T. has to exercise in each of the remaining weeks. How many hours will J.T. have to exercise each week to receive gym credit? Enter your inequality, answer, and work in the box provided.
Mathematics
1 answer:
VARVARA [1.3K]3 years ago
8 0

Answer:

H >= 6.25

6.5 hours per week

Step-by-step explanation:

75-50=25

JT must complete 25 more hours of exercise in 4 weeks.  25/4=6.25.  So JT has to exercise 6.5 hours each week.

>= (means greater than or equal to)

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4 0
3 years ago
Write a vector equation of the line that passes through P(4, 7) and is parallel to a = (3, 8).
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Answer:

B

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(x,y) = P + (a)t

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3 years ago
Given the position of the particle, what the position(s) of the particle when it’s at rest
choli [55]

The position function of a particle is given by:

X\mleft(t\mright)=\frac{2}{3}t^3-\frac{9}{2}t^2-18t

The velocity function is the derivative of the position:

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The particle will be at rest when the velocity is 0, thus we solve the equation:

2t^2-9t-18=0

The coefficients of this equation are: a = 2, b = -9, c = -18

Solve by using the formula:

t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}

Substituting:

\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}

We have two possible answers:

\begin{gathered} t=\frac{9+15}{4}=6 \\ t=\frac{9-15}{4}=-\frac{3}{2} \end{gathered}

We only accept the positive answer because the time cannot be negative.

Now calculate the position for t = 6:

undefined

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