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kondaur [170]
3 years ago
7

Abdul drove four trips that totaled 426km. The second trip was 4 less than double the first. THE THIRD TRIP WAS DOUBLE THE SECON

D AND THE FOURTH TRIP WAS 18 MORE THAN TRIPLE THE FIRST HOW FAR WAS EACH TRIP
Mathematics
1 answer:
Alexus [3.1K]3 years ago
6 0
Say the first trip was x.
The second trip would be 2x-4.
The third would be 2(2x-4) = 4x-8
The forth would be 3x+18

The total of these would be x + 2x - 4 + 4x - 8 + 3x + 18
This can be simplified to 10x + 6

This means that 10x+6 = 426
Minus 6 from both sides
10x = 420
Divide both sides by 10
x = 42

Trip 1 = x = 42km
Trip 2 = 2x-4 = 84-4 = 80km
Trip 3 = 4x-8 = 168-8 = 160km
Trip 4 = 3x+18 = 126+18 = 144km
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Step-by-step explanation:

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Find the side length of each irregular polygon.
Burka [1]

Answer:

Step-by-step explanation:

Polygon #1

40 + 33 + 23 + 25 + 30 = 151 ft

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65 + 57 + 66 = 188 ft

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I hope I helped you.

4 0
4 years ago
Please Help me ASAP read the problem below
SashulF [63]

PART 1: Find the surface area of each section.

The formula for finding the area of a triangle is A = 1/2(b)(h); where b = base length and h = height. And the formula for finding the area of a rectangle is A = (l)(w); where l = length and w = width.

I'll start with the gold triangles, which are both the same size so I only need to calculate once.

A = 1/2(b)(h)

A = 1/2(7)(8.6)

A = 1/2(60.2)

A = 30.1 cm²

Now, I'll find the area of the blue triangles.

A = 1/2(b)(h)

A = 1/2(12)(7)

A = 1/2(84)

A = 42 cm²

Now, I'll find the area of the rectangular base.

A = (l)(w)

A = (12)(7)

A = 84 cm²

PART 2: Find the amount of foil in each color needed to cover 1 ornament.

There are two gold triangles, so all we have to do is multiply the area of the gold triangle by 2.

(30.1)(2) = 60.2 cm²

There are two blue triangles, so all we have to do it multiply the area of the blue triangle by 2.

(42)(2) = 84 cm²

And Olga will need 84 cm² of black foil to cover the rectangular base.

PART 3: Find the total amount of foil needed to cover 1 ornament and then 100 ornaments.

To find the total amount of foil needed, just add the amounts found in the previous step.

60.2 + 84 + 84 = 228.2 cm²

Olga will need 228.2 cm² of foil to cover 1 ornament.

(228.2)(100) = 22820 cm²

Olga will need 22, 820 cm² of foil to cover 100 ornaments.

PART 4: Fill in the blanks to give your answer.

Surface area of black face(s) = 84 cm²

Surface area of blue face(s) = 84 cm²

Surface area of gold face(s) = 60.2 cm²

Total surface area of 1 ornament = 228.2 cm²

Total surface area of 100 ornaments = 22, 820 cm²

Hope this helps!

3 0
4 years ago
One quantity of interest is maximum height. What other quantity might be of interest?
3241004551 [841]

The other quantity which might be of interest is initial velocity

<h3>What is maximum height?</h3>

The maximum height of the object can be defined as the highest vertical position along its trajectory line.

The range of the projectile is also known as the horizontal displacement of the projectile. It is largely dependent on the initial velocity of the object.

If;

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  • θ = angle of the initial velocity from the horizontal plane (radians or degrees).

Maximum height of projectile is given by the formula:

H = \frac{vo^2sin^2\alpha }{2g}

From this, we can deduce that another quantity of interest is initial velocity

Thus, the other quantity which might be of interest is initial velocity

Learn more about maximum height here:

brainly.com/question/12446886

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4 0
2 years ago
6/8-1/26/8 - 1/2 equals
Lilit [14]
\frac{6}{8} -   \frac{\frac{1}{26}}{8} - \frac{1}{2}= \frac{51}{208}
5 0
3 years ago
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