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wel
3 years ago
14

Please answer correctly will mark brainliest, thanks!

Mathematics
1 answer:
monitta3 years ago
3 0
2 first class tickets
4 coach tickets

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Roger has two golden retrievers, Sadie and Buddy. buddy weighs 14 pounds more than Sadie. If their total weight is 136 pounds, h
ra1l [238]
Sadie= 82
Buddy= 54
Divide by 2, 136/2=68, then rest 14 to one half, 68-14=54, next add the other half 14, 68+14=82.
There you have it, i hope it helps you
6 0
3 years ago
Which could be the first step in simplifying this expression? Check all that apply. (x cubed x Superscript negative 6 Baseline)
PtichkaEL [24]

Answer:

(x^{-3} )^{2}

x^6 x^{-12}

Step-by-step explanation:

(x^{3} x^{-6} )^{2} is the expression given to be solved.

First of all let us have a look at <u>3 formulas</u>:

1.\ p^a \times p^b = p^{(a+b)}\\2.\ (p^a \times q^b)^c = (p^{a})^c \times (q^{b})^c\\3.\ (p^a)^b = p^{a\times b}

Both the formula can be applied to the expression((x^{3} x^{-6} )^{2}) during the first step while solving it.

<u>Applying formula (1):</u>

(x^{3} x^{-6} )^{2}

Comparing the terms of (x^{3} x^{-6} ) with p^a \times p^b

p=x, a =3, b=-6

\Rightarrow x^{3+(-6)}\\\Rightarrow x^{3-6}\\\Rightarrow x^{-3}

So, (x^{3} x^{-6} )^{2} is reduced to (x^{-3} )^{2}

<u>Applying formula (2):</u>

Comparing the terms of (x^{3} x^{-6} )^{2} with (p^a \times q^b)^c

p=q=x, a =3, b=-6, c=2

\Rightarrow (x^{3})^2\times (x^{-6})^2\\\text{Applying Formula (3)}\\x^6 x^{-12}

So, (x^{3} x^{-6} )^{2} is reduced to x^6 x^{-12}.

So, the answers can be:

(x^{-3} )^{2}

x^6 x^{-12}

8 0
3 years ago
Date
Yakvenalex [24]

Answer:

Friday, Feb. 8, at 3:16 p.m.

Step-by-step explanation:Just took it :3

5 0
3 years ago
Read 2 more answers
your patient has a 2500 cc bag of irrigation solution hanging, and 750 cc of fluid has been infused. what percentage of irrigati
nlexa [21]

Answer:  30%

Step-by-step explanation:

Given : Patient has a 2500 cc bag of irrigation solution hanging.

Irrigation has been infused = 750cc

Then, the percentage of irrigation solution has been infused :

\dfrac{\text{ fluid infused}}{\text{Total irrigation solution}}\times100\\\\=\dfrac{750}{2500}\times100\\\\= 30\%

Hence, the percentage of irrigation solution has been infused = 30%

6 0
3 years ago
Divide using synthetic division (3y^4-13y^3+12y^2-33y+9)/(y-4)
tatiyna
3y³-y²+8y-1+5/y-4. is that unless you want the answer smaller
3 0
3 years ago
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