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3 years ago

Please answer correctly will mark brainliest, thanks!

Mathematics

1 answer:

monitta3 years ago

3 0

2 first class tickets
4 coach tickets

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Roger has two golden retrievers, Sadie and Buddy. buddy weighs 14 pounds more than Sadie. If their total weight is 136 pounds, h

ra1l [238]

Sadie= 82
Buddy= 54
Divide by 2, 136/2=68, then rest 14 to one half, 68-14=54, next add the other half 14, 68+14=82.
There you have it, i hope it helps you

6 0

3 years ago

Which could be the first step in simplifying this expression? Check all that apply. (x cubed x Superscript negative 6 Baseline)

PtichkaEL [24]

Answer:

$(x^{-3} )^{2}$

$x^6 x^{-12}$

Step-by-step explanation:

$(x^{3} x^{-6} )^{2}$ is the expression given to be solved.

First of all let us have a look at 3 formulas:

$1.\ p^a \times p^b = p^{(a+b)}\\2.\ (p^a \times q^b)^c = (p^{a})^c \times (q^{b})^c\\3.\ (p^a)^b = p^{a\times b}$

Both the formula can be applied to the expression( $(x^{3} x^{-6} )^{2}$ ) during the first step while solving it.

Applying formula (1):

$(x^{3} x^{-6} )^{2}$

Comparing the terms of $(x^{3} x^{-6} )$ with $p^a \times p^b$

$p=x, a =3, b=-6$

$\Rightarrow x^{3+(-6)}\\\Rightarrow x^{3-6}\\\Rightarrow x^{-3}$

So, $(x^{3} x^{-6} )^{2}$ is reduced to $(x^{-3} )^{2}$

Applying formula (2):

Comparing the terms of $(x^{3} x^{-6} )^{2}$ with $(p^a \times q^b)^c$

$p=q=x, a =3, b=-6, c=2$

$\Rightarrow (x^{3})^2\times (x^{-6})^2\\\text{Applying Formula (3)}\\x^6 x^{-12}$

So, $(x^{3} x^{-6} )^{2}$ is reduced to $x^6 x^{-12}$ .

So, the answers can be:

$(x^{-3} )^{2}$

$x^6 x^{-12}$

8 0

3 years ago

Date

Yakvenalex [24]

Answer:

Friday, Feb. 8, at 3:16 p.m.

Step-by-step explanation:Just took it :3

5 0

3 years ago

Read 2 more answers

your patient has a 2500 cc bag of irrigation solution hanging, and 750 cc of fluid has been infused. what percentage of irrigati

nlexa [21]

Answer: 30%

Step-by-step explanation:

Given : Patient has a 2500 cc bag of irrigation solution hanging.

Irrigation has been infused = 750cc

Then, the percentage of irrigation solution has been infused :

$\dfrac{\text{ fluid infused}}{\text{Total irrigation solution}}\times100\\\\=\dfrac{750}{2500}\times100\\\\= 30\%$

Hence, the percentage of irrigation solution has been infused = 30%

6 0

3 years ago

Divide using synthetic division (3y^4-13y^3+12y^2-33y+9)/(y-4)

tatiyna

3y³-y²+8y-1+5/y-4. is that unless you want the answer smaller

3 0

3 years ago