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Wittaler [7]
3 years ago
9

Is 9/31 an irrational number

Mathematics
2 answers:
elena55 [62]3 years ago
5 0

Answer:No


Step-by-step explanation:

tatyana61 [14]3 years ago
5 0

Answer:

No, 9/31 is not an irrational number.

Step-by-step explanation:

A real number is called rational number when it can be expressed in the form of  \frac{p}{q},

Where, both p and q are integers and q ≠ 0,

Otherwise, it is called irrational number.

Here, the given number is,

\frac{9}{31}

Since,both 9 and 31 are integers,

Also, 31 ≠ 0,

⇒ 9/31 is a rational number,

Hence, It is not an irrational number.

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\displaystyle
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<em>-------------------------------------------------------------</em>


\displaystyle&#10;(x^2+y)^n=\sum_{k=0}^n\binom{n}{k}x^{2n-2k}y^k\\&#10;n=5\\&#10;k=3\\\\\binom{5}{3}=\dfrac{5!}{3!2!}=\dfrac{4\cdor5}{2}=10

<u>It's 10.</u>

----------------------------------------------------

\displaystyle&#10;(3x^2+y)^n=\sum_{k=0}^n\binom{n}{k}(3x)^{2n-2k}y^k=\sum_{k=0}^n\binom{n}{k}\cdot 3^{2n-2k}\cdot x^{2n-2k}y^k\\\\&#10;n=5\\&#10;k=4\\\\&#10;\binom{5}{3}\cdot3^{2\cdot5-2\cdot4}=10\cdot3^{2}=10\cdot9=90

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6 0
3 years ago
270 american dollar and recevied 3000 pesos when he returned from mexico he had 100 pesos left. how many will he recevie when he
AURORKA [14]
To solve this problem we can use simple proportion
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