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nydimaria [60]
3 years ago
7

11 3/4-7 1/4 evaluate answer need asap

Mathematics
1 answer:
Debora [2.8K]3 years ago
8 0

Answer:

−6

Step-by-step explanation:

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36 out of 100 randomly selected taxpayers knew about tax incentives for installing energy-saving furnaces. Find a 90% confidence
tresset_1 [31]

Answer:

The 90% confidence interval for the population proportion who knew about the incentives is (0.28, 0.44).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 100, \pi = \frac{36}{60} = 0.6

90% confidence level

So \alpha = 0.1, z is the value of Z that has a pvalue of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.36 - 1.645\sqrt{\frac{0.36*0.64}{100}} = 0.28

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.36 + 1.645\sqrt{\frac{0.36*0.64}{100}} = 0.44

The 90% confidence interval for the population proportion who knew about the incentives is (0.28, 0.44).

7 0
3 years ago
A hair salon receives a shipment of 84 bottles of hair conditioner to use and sell to customers. The two types are labels type A
Rom4ik [11]
x-\ botlle\ A\\y-\ bottle\ B\\\\ \left \{ {{x+y=84} \atop {6,5x+8,25y=588}} \right. \\\\ \left \{ {{x=84-y} \atop {6,5x+8,25y=588}} \right. \\\\Substitution\ method\\\\
6,5(84-y)+8,25y=588\\\\
546-6,5y+8,25y=588\ \ \ | subtract\ 546
1,75y=42\ \ \| divide\ by\ 1,75\\\\y=24\\\\There\ were\ 24\ bottles\ B\ and\ 42\ bottle\ A.
6 0
3 years ago
Find the midpoint of the segment with the given endpoints (5,-9) and (-2,-2)
QveST [7]
Another way to solve this is to use the Midpoint Formula.  The midpoint of a segment joining points (x_1,y_1) and (x_2,y_2) is

\left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} \right)

So the midpoint of your segment is

\left(\frac{5+(-2)}{2},\frac{-9+(-2)}{2}\right) = \left(\frac{3}{2},-\frac{11}{2} \right)

Perhaps it helps to see that the x-coordinate of the midpoint is just the average of the x-coordinates of the points.  Ditto for the y-coordinate of the midpoint; just average the y's.
6 0
3 years ago
Please answer this now in 2 minutes
ValentinkaMS [17]

Answer:

(1, 2)

Step-by-step explanation:

x2-x1/2, y2-y1/2

Plug in the values, and you should get (1, 2)

7 0
3 years ago
Read 2 more answers
ABC Auto Insurance classifies drivers as good, medium, or poor risks. Drivers who apply to them for insurance fall into these th
Misha Larkins [42]

Answer:

a.P(E_1/A)=0.0789

b.P(E_2/A)=0.395\

c.P(E_3/A)=0.526

Step-by-step explanation:

Let E_1,E_2,E_3 are the events that denotes the good drive, medium drive and poor risk driver.

P(E_1)=0.30,P(E_2)=0.50,P(E_3)=0.20

Let A be the event that denotes an accident.

P(A/E_1)=0.01

P(A/E_2=0.03

P(A/E_3)=0.10

The company sells Mr. Brophyan insurance policy and he has an accident.

a.We have to find the probability Mr.Brophy is a good driver

Bayes theorem,P(E_i/A)=\frac{P(A/E_i)\cdot P(E_1)}{\sum_{i=1}^{i=n}P(A/E_i)\cdot P(E_i)}

We have to find P(E_1/A)

Using the Bayes theorem

P(E_1/A)=\frac{P(A/E_1)\cdot P(E_1)}{P(E_1)\cdot P(A/E_1)+P(E_2)P(A/E_2)+P(E_3)P(A/E_3)}

Substitute the values then we get

P(E_1/A)=\frac{0.30\times 0.01}{0.01\times 0.30+0.50\times 0.03+0.20\times 0.10}

P(E_1/A)=0.0789

b.We have to find the probability Mr.Brophy is a medium driver

P(E_2/A)=\frac{0.03\times 0.50}{0.038}=0.395

c.We have to find the probability Mr.Brophy is a poor driver

P(E_3/A)=\frac{0.20\times 0.10}{0.038}=0.526

7 0
4 years ago
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