Answer:
their price at $11.50 for maximum revenue
Explanation:
given data
seating capacity = 15000
ticket prices = $12
average attendance game = 11000
average attendance increase = 1000
solution
we consider here Revenue function is R and that is express as
Revenue function R = Price of ticket × booked seats .....................1
here number of time lowered the price of ticket n = $1
so here price will be as
price = $12 - ( n × $1)
price = $(12 - n) ................2
so here Quantity will express as
Quantity = number of sold tickets + n (1000)
Quantity = 1100 + n (1000) Spectators ..................3
so R(n) will be
R(n) = 12-n (11000 + 1000n)
R(n) = 132,000 + 1000n - 1000n²
R(n) = -1000 (x² - x - 132)
R(n) = -1000 ( (x - 0.5)² - )
so
R(n) = -1000 (x - 0.5)² + 132,250
R(n) - 13,250 = -1,000 (x - 0.5)²
solve it we get
n = 0.5 ..........4
so from equation 2
price = 12 - 0.5
price = $11.50
so from equation 3
Spectators = 11,000 + 1,000 (0.5)
Spectators = 11,500
and
Revenue = $13,250
so that here set their price at $11.50 for maximum revenue