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3 years ago

Sexually-reproducing species have an advantage over asexually-reproducing species in their ability to

Biology

2 answers:

REY [17]3 years ago

8 0

Sexually reproducing species have the ability to produce genetically variation in the offspring.

<u>Explanation:</u>

Sexual reproduction comprises two parents and the joining of male and female organisms when fertilization takes place.
The offspring acquires a mixture of genes from both progenitors, so they are distinct from each other and their parents.
In asexual reproduction, only one progenitor plays the role of producing the offspring which is identical to it.
The newly formed offspring from sexual reproduction possess the characteristics of both the parents but in asexual reproduction, the offspring possess the characteristic of one parent only.
In sexual reproduction, both male and female exchange their DND genetic material, as a result, a wider variety of gene combinations can be found in the resulting offspring.

maw [93]3 years ago

5 0

The sexual reproduction helps in having more variation among the offsprings. It also makes the offsprings more resistant to genetic diseases.

<h3><u>Explanation</u>:</h3>

Sexual reproduction is the process by which the gametes of the species fused together to form zygote which develops into an offspring. This offspring produced has the gene from both the parents . This genetic setup is not only copied from the parents but they undergo the crossing over and independent assortment which leads to variation among the offspring itself as well as they differ from their parents too.

This variation among the offspring as well as the crossing over helps to eleminate the lethal genes from the genetic pool. Thereby they help to get more resistance among the offsprings from diseases.

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Mitosis is a process of nuclear division in eukaryotic cells that occurs when a parent cell divides to produce two identical daughter cells. During cell division, mitosis refers specifically to the separation of the duplicated genetic material carried in the nucleus.

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PLS HELP WILL GIVE 50 PONITS+ MARK BRAINLYEST IF DO What has developed as a result of population growth around Cape Canaveral du

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New homes has developed as a result of population growth around Cape Canaveral due to the space program.

<h3>What is population growth?</h3>

The rise in the number of people on Earth is referred to as population growth.
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2 years ago

Which phrase best describes the benthic zone of a lake?

Vaselesa [24]

Answer:

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Explanation:

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3 years ago

What happens to the genetics of a population when an invasive species enters

tekilochka [14]

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3 years ago

the couple is also concerned about their child inheriting hemophilia, another rare disease, which is x-linked. natalie’s brother

IgorC [24]

Hemophilia is a recessive X-linked condition and is inherited from parents. . The probability that Natalie and Daniel’s first child has hemophilia is<u> 1/4</u>, not 1/8. The statement is<u> false.</u>

<h3>What is an X-linked gene?</h3>

When talking about sex-linked genes, we refer to all those genes located in one of the sex-chromosomes and not in the somatic ones.

X-linked genes are the genes located specifically in the X sex chromosome.

Traits coded by these genes are inherited. This is, X-linked genes are transmitted from parents to children through generations.

According to this, X-linked genetic disorders will be inherited as well.

Men have a high probability of being affected since they only have one copy of the X chromosome.

In women, the effect of the mutation might be musk in heterozygous state if the mutation is recessive.

Hemophilia is a recessive X-linked disorder, which means it is coded by the recessive allele.

X+ ⇒ X chrosomosome with Dominant allele

X- ⇒ X chrosomosome with Recessive allele

<u>Genotype Phenotype</u>

X+X+ Healthy woman

X+X- Healthy carrier woman

X-X- Hemophilic woman

X+Y Healthy man

X-Y Hemophilic man

Let us make a pedigree of these families,

<u>Natalie's family</u>:

Mother healthy carrier X+X-

Father healthy X+Y

Brother hemophilic X-Y

Natalie Healthy X+X- or X+X+

Natalie has 1/2 chances of being carrier X+X- and 1/2 of being X+X+.

<u>Daniel's family</u>:

Mother healthy carrier X+X-

Father hemophilic X-Y

Sister hemophilic X-X-

Daniel Healthy X+Y

He has 1/2 chances of being healthy X+Y and 1/2 of being affected X-Y.

According to the product probability rule, if events A and B are independent from each other, the probability of occurrence of both events together is

P(A∩B) = P(A) x P(B)

In this case,

event A is Daniel being affected ⇒ 1/2
event B is Natalie being carrier ⇒ 1/2

P(A∩B) = P(A) x P(B) = 1/2 x 1/2 = 1/4

The probability that Natalie and Daniel’s first child has hemophilia is 1/4, not 1/8. The statement is<u> false.</u>

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1 year ago