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butalik [34]
3 years ago
15

PLEASE HURRY

Mathematics
1 answer:
Delvig [45]3 years ago
4 0

Answer:

Answer 2) When dividing by -5, he did not change the \leq to \geq.

Step-by-step explanation:

If you divide or multiply a negative, you ALWAYS change the sign to its opposite.

Hope this helps! :)

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BRAINLEST PLUS 10 PTS <br> Solve for x pls
Anna11 [10]

Answer:

x=39

Step-by-step explanation:

3 0
3 years ago
2a+ 4b +30<br><br><br> 16 points
oee [108]

Answer:

2(a+2b+15)

Step-by-step explanation:

hope this helps!

8 0
3 years ago
jack bought 3 slices of cheese pizza and 4 slices of nushroom pizza for a total cost of $12.50. Grace bought 3 slices of cheese
Llana [10]
The cost of one slice of mushroom pizza is $2.00 dollars. This is solved by subtracting the equations:  
X = cheese pizza 
Y = mushroom pizza  
(3X + 4Y = 12.50) 
- (3X + 2Y = 8.50)
 ______________ 
2Y = 4.00 
Y=2 or a slice of mushroom pizza is $2.00.
4 0
3 years ago
. Could someone please explain this to me in detail. I am very confused. Thank you so much!. . A candle is 17 inches tall after
andrew-mc [135]

The generic equation of the line is:

H-H0 = m (T-T0)

Where,

m: slope of the line

(T0, H0): ordered pair belonging to the line.

The slope of the line is:

m =\frac{H2-H1}{T2-T1}

Substituting values we have:

m =\frac{15-17}{5-3}

Rewriting:

m =\frac{-2}{2}

m = -1

Then, choosing an ordered pair we have:

(T0, H0) :( 5, 15)

Substituting values we have:

H-15=-(T-5)

Rewriting the equation:

H-15=-T+5

H=-T+5+15

H=-T+20

Then, for 8 hours we have:

H=-8+20

H=12

Answer:

a linear equation to model the relationship between height H of the candle, and T time is:

H=-T+20

the candle will be 12 inches after burning 8 hours

7 0
3 years ago
Read 2 more answers
luke jogged a total of 56.5 miles last week. if luke jogged the same distance,d, each day for 3 days and half that distance on e
Leokris [45]
The algebraic equation used to answer this question is:
3d + 4(1/2d) = 56.5
This is because he ran d, the distance, three times that week. For the rest of the four days, he ran 1/2 the distance, or half d.
To find the answer, you first distribute:
3d + 2d = 56.5
Add like terms:
5d = 56.5
Divide both side by 5:
5d/5 = 56.5/5
d = 11.3
On the first three days, Luke jogged 11.3 miles. On the remaining days, where he jogged 1/2d, Luke jogged 5.65 miles.
Hope this helps!
3 0
3 years ago
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