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Schach [20]
3 years ago
12

The triangles are similar. Write a Similarity statement for the triangles

Mathematics
2 answers:
malfutka [58]3 years ago
8 0

Answer:

c

Step-by-step explanation:

big       small

nqr      npm

vlada-n [284]3 years ago
8 0

Answer:

<h2>Third option.</h2>

\triangle NPM \sim \triangle NQR

Step-by-step explanation:

By given, we know that both triangles are similar, that means their sides are proportional and their angle are congruent. However, we need to be careful when we write the similarity statement, because all corresponding vertex must be in the same position.

For example, from the image, we can deduct that the similarities are

\triangle NPM \sim \triangle NQR\\\triangle PMN \sim \triangle QRN\\\triangle MNP \sim \triangle RNQ\\\triangle NMP \sim \triangle NRQ

Each statement is true, based on the similarity provided by the problem.

Now, let's see which option has one of this similarities.

You can observe that the first option is not the right answer because, the triangle NPM doesn't correspond to triangle RNQ.

Similarly, the second choice is not correct, because triangle NPM is no similar to triangle NRQ.

However, the third choice is the right answer, because triangle NPM corresponds to triangle NQR, they are similar.

Therefore, the right answer is the third choice: \triangle NPM \sim \triangle NQR

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8 0
3 years ago
2 less then 3 times a number is 9
Masteriza [31]

\huge\boxed{\text{As an expression:}\ 3x-2=9}

\huge\boxed{\text{Solved for x:}\ x=\frac{11}{3}}

Let's start with "3 times a number". We will use x to represent the number. 3x

"2 less than" is next. -2

Finally, "is 9". =9

Put it all together to get an expression. \boxed{3x-2=9}

Now, let's solve for the unknown number.

Add 2 on both sides of the equation. 3x=11

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5 0
3 years ago
Read 2 more answers
Separate the number 18 into two parts where the product of those parts is 77
mart [117]
Answer: 11, 7

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3 0
3 years ago
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Andrew is about to leave for school. If he walks at a speed of 50 meters per minute, he will arrive 3 minutes after the bell rin
Mariana [72]

Answer:

The answer is: 13 minutes

Step-by-step explanation:

First Let us form equations with the statements in the two scenario

time=\frac{distance}{speed}

Let the time in which the bell rings be 'x'

1. If Andrew walks (50 meters/minute), he arrives 3 minutes after the bell rings. Therefore the time of arrival at this speed = (3 + x) minutes

3 + x =\frac{distance}{50}\\distance = 50(3+x) - - - - - (1)

2. If Andrew runs (80 meters/minute), he arrives 3 minutes before the bell rings. Therefore the time taken to travel the distance = (x - 3) minutes

x - 3 = \frac{distance}{80} \\distance = 80(x-3)   - - - - - (2)

In both cases, the same distance is travelled, therefore, equation (1) = equation (2)

50(3+x)=80(x-3)

150 +50x=80x-240\\

Next, collecting like terms:

150 + 240 = 80x - 50x\\390 = 30x\\30x = 390\\

dividing both sides by 3:

x =  390÷30 = 13

∴ x = 13 minutes

7 0
3 years ago
NOTE -- THIS QUESTION HAS BEEN ANSWERED ALREADY!!!
DanielleElmas [232]

Answer:

The cubic polynomial is: x³ - x² - 6x.

Step-by-step explanation:

Given the degree and the roots of the polynomial we can find it.

An n - degree polynomial has n roots.

Here, given that the degree of the polynomial is 3 and three roots are given. Also, if (x - a) is a factor of a polynomial then x = a is a root of the polynomial. The converse is also true.

Since, the roots of the polynomial are given to -2, 0, 3 then it should have had the following factors.

(x + 2)(x - 0)(x - 3) = 0

Multiplying them we get:

⇒ $ (x^2 + 2x)(x - 3) $

$ = x^3 - 3x^2 + 2x^2 - 6x $

$ = x^3 - x^2 - 6x $ which is the required cubic polynomial.

Hence, the answer.

4 0
3 years ago
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